Simple Harmonic Motion, Resonance, and FEM Modal Analysis

Category: Physics Fundamentals | 2026-03-25 | サイトマップ
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Table of Contents
  1. The Bridge That Destroyed Itself
  2. Simple Harmonic Motion: x = A cos(ωt + φ)
  3. Natural Frequency: ωn = √(k/m)
  4. Damped Oscillation and Damping Ratio
  5. Forced Vibration and Resonance
  6. Multi-DOF Systems and Mode Shapes
  7. FEM Modal Analysis
  8. Campbell Diagram for Rotating Machinery
  9. Cross-Topics

1. The Bridge That Destroyed Itself

On November 7, 1940, the Tacoma Narrows Bridge in Washington State collapsed spectacularly in a moderate 67 km/h wind. The bridge had been open for only four months. The collapse is one of the most famous engineering disasters in history — and it's a textbook lesson in resonance.

The bridge had a long, flat, and relatively narrow deck — aerodynamically prone to vortex shedding. As wind flowed around the deck, alternating vortices were shed alternately from the top and bottom edges (Kármán vortex street), creating an oscillating lift force. When the vortex shedding frequency matched the bridge's torsional natural frequency, the amplitude of oscillation grew without bound — resonance. Within hours, the deck was twisting ±45° and ultimately failed.

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Why did the bridge collapse from wind? I mean, wind is slow — it's not like a sudden impact. How does something gentle like wind build up enough energy to destroy a bridge?

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Resonance. It's not about the wind being powerful — it's about the timing. The vortex shedding happened to create a force that matched the bridge's natural torsional frequency. Every cycle, the wind added a tiny bit of energy and the structure absorbed it. Because the wind frequency and the structural frequency were synchronized, each push came at exactly the right moment to add to the growing oscillation instead of fighting it. With very low damping in the bridge (no damping devices), there was nothing removing energy. After hours of this, the amplitude grew to the point where the structure failed. The lesson for modern bridge design: add aerodynamic stabilizers, increase damping, or detune the natural frequency away from expected wind-forcing frequencies.

2. Simple Harmonic Motion: x = A cos(ωt + φ)

Simple Harmonic Motion (SHM) occurs when a restoring force is proportional to displacement and directed toward equilibrium. The equation of motion for an undamped mass-spring system:

$$m\ddot{x} + kx = 0$$

The solution is oscillatory:

$$x(t) = A\cos(\omega_n t + \varphi)$$

Where $A$ is amplitude (m), $\omega_n$ is natural angular frequency (rad/s), and $\varphi$ is initial phase (rad). The velocity and acceleration are:

$$\dot{x} = -A\omega_n \sin(\omega_n t + \varphi), \qquad \ddot{x} = -A\omega_n^2 \cos(\omega_n t + \varphi)$$

Key insight: the maximum acceleration = $A\omega_n^2$. For high-frequency vibration with even modest amplitude, accelerations can be enormous — this is why high-frequency vibration of electronics (printed circuit boards, connectors) causes fatigue failure even with sub-millimeter amplitudes.

3. Natural Frequency: ωn = √(k/m)

The natural frequency of an undamped SDOF system:

$$\omega_n = \sqrt{\frac{k}{m}} \quad \text{(rad/s)}, \qquad f_n = \frac{\omega_n}{2\pi} \quad \text{(Hz)}, \qquad T_n = \frac{1}{f_n} \quad \text{(s)}$$

This simple formula contains enormous insight: to increase natural frequency (stiffen a structure against resonance), increase $k$ or reduce $m$. Both are common design strategies.

Structure / ComponentTypical Natural FrequencyEngineering Concern
Tall building (50+ stories)0.1–0.3 HzWind gusts, seismic loading
Highway bridge1–5 HzTraffic loading, wind
Automotive body (bending)25–35 HzRoad noise, engine vibration
Engine mount6–12 HzEngine firing frequency isolation
PCB / electronics board50–500 HzVibration fatigue of solder joints
Turbine blade (1st flap)200–2000 HzEngine excitation harmonics

4. Damped Oscillation and Damping Ratio

Real structures always have some energy dissipation — material damping, friction at joints, aerodynamic drag. The damped SDOF equation:

$$m\ddot{x} + c\dot{x} + kx = 0$$

The critical damping coefficient: $c_{\text{cr}} = 2\sqrt{km} = 2m\omega_n$. The dimensionless damping ratio:

$$\zeta = \frac{c}{c_{\text{cr}}} = \frac{c}{2m\omega_n}$$

Solution for underdamped case ($\zeta < 1$):

$$x(t) = Ae^{-\zeta\omega_n t}\cos(\omega_d t + \varphi), \qquad \omega_d = \omega_n\sqrt{1-\zeta^2}$$
Damping Ratio ζBehaviorExample
ζ = 0Undamped: oscillates foreverTheoretical (no real system)
0 < ζ < 1Underdamped: decaying oscillationMost structures (ζ = 0.01–0.05)
ζ = 1Critically damped: fastest return, no oscillationDoor closers, some shock absorbers
ζ > 1Overdamped: slow return, no oscillationHeavy oil dashpot
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My FEM model has Rayleigh damping with α=0.5 and β=0.0001. How do I know what damping ratio that gives at a specific frequency?

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Rayleigh damping gives a frequency-dependent damping ratio: $\zeta = \frac{\alpha}{2\omega} + \frac{\beta\omega}{2}$. At, say, 100 Hz (ω = 628 rad/s): $\zeta = 0.5/(2×628) + 0.0001×628/2 = 0.000398 + 0.0314 ≈ 3.2\%$. At 10 Hz (ω = 62.8 rad/s): $\zeta = 0.5/(125.6) + 0.0001×31.4 ≈ 0.4\% + 0.3\% = 0.7\%$. Rayleigh damping rises linearly with frequency (β term) and drops with frequency (α term), creating a characteristic U-shape. The two parameters are typically calibrated to match target damping ratios at two specific frequencies of interest.

5. Forced Vibration and Resonance

When an external harmonic force $F_0\cos(\Omega t)$ drives a SDOF system, the steady-state response amplitude is:

$$X = \frac{F_0/k}{\sqrt{(1-r^2)^2 + (2\zeta r)^2}}, \qquad r = \frac{\Omega}{\omega_n}$$

Where $r$ is the frequency ratio. The dynamic amplification factor (DAF) is the ratio $X / (F_0/k)$ — how much larger is the dynamic response compared to the static response?

At resonance ($r = 1$, $\Omega = \omega_n$): DAF = $\frac{1}{2\zeta}$. For typical structural damping of 1% ($\zeta = 0.01$): DAF = 50! The dynamic response is 50 times larger than the static response. This is why resonance is so destructive.

Resonance Avoidance Design Rules

  • Frequency separation: Keep $f_n$ at least 20–30% away from any expected excitation frequency
  • Detuning: Add or remove mass/stiffness to shift $f_n$ away from excitation
  • Damping: Add viscoelastic damping layers, tuned mass dampers, or friction dampers
  • Isolation: Mount equipment on soft isolators so the transmitted excitation doesn't reach the structure's natural frequency

6. Multi-DOF Systems and Mode Shapes

A real structure has infinitely many DOF (or $N$ DOF in FEM). The undamped free vibration problem becomes an eigenvalue problem:

$$[\mathbf{K}]\boldsymbol{\phi}_i = \omega_i^2 [\mathbf{M}]\boldsymbol{\phi}_i$$

Where $\omega_i$ are the natural frequencies (eigenvalues) and $\boldsymbol{\phi}_i$ are the mode shapes (eigenvectors). Each mode shape describes the spatial pattern of deformation at that natural frequency.

Modal properties:

  • Mass-orthogonality: $\boldsymbol{\phi}_i^T [\mathbf{M}] \boldsymbol{\phi}_j = 0$ for $i \neq j$
  • Stiffness-orthogonality: $\boldsymbol{\phi}_i^T [\mathbf{K}] \boldsymbol{\phi}_j = 0$ for $i \neq j$
  • Modal mass: $m_i^* = \boldsymbol{\phi}_i^T [\mathbf{M}] \boldsymbol{\phi}_i$
  • Modal stiffness: $k_i^* = \boldsymbol{\phi}_i^T [\mathbf{K}] \boldsymbol{\phi}_i = \omega_i^2 m_i^*$

Orthogonality is the mathematical miracle that makes modal analysis work: the coupled MDOF system decomposes into $N$ independent SDOF equations in modal coordinates. Each mode can be solved independently.

8. Campbell Diagram for Rotating Machinery

For rotating machinery (engines, turbines, fans), the excitation frequencies are multiples of the rotation speed (engine orders). A Campbell diagram plots natural frequencies (horizontal lines) and engine orders (diagonal lines) against rotation speed:

$$f_{\text{excitation}} = n \times \frac{N}{60} \quad \text{Hz}$$

Where $n$ is the engine order (1×, 2×, etc.) and $N$ is speed in RPM. Crossings of a natural frequency line and an engine order line are potential resonance points. The Campbell diagram helps designers ensure no problematic resonance crossings occur at sustained operating speeds.

For a 4-cylinder 4-stroke engine at 3000 RPM: the primary firing order excitation is the 2nd engine order = 2 × 3000/60 = 100 Hz. Any structural component with a natural frequency near 100 Hz will be excited heavily at cruise speed — a classic NVH design issue.

9. Cross-Topics

TopicConnectionLink
Hooke's LawF=-kx is the restoring force that produces SHMSprings & Hooke's Law
Wave PropertiesWaves are SHM propagating through spaceWave Properties
Circular MotionSHM is the projection of uniform circular motionCircular Motion & Centrifugal Force
Newton's LawsSHM equation mẍ+kx=0 comes directly from F=maNewton's Laws of Motion
Vibration & DynamicsFull MDOF dynamics, response spectrum, random vibrationVibration & Dynamics