Momentum and Impulse — Airbag Physics and Explicit FEM Impact Analysis

Category: Physics Fundamentals | 2026-03-25 | サイトマップ
NovaSolver Contributors
Table of Contents
  1. Momentum and Impulse in Engineering
  2. Linear Momentum: p = mv
  3. Impulse: J = FΔt = Δp
  4. Airbag Design: Impulse in Action
  5. Conservation of Momentum
  6. Elastic and Inelastic Collisions
  7. Momentum Methods in Explicit FEM
  8. Angular Momentum and Rotating Structures
  9. Cross-Topics

1. Momentum and Impulse in Engineering

Momentum ($p = mv$) and its time-rate-of-change version — impulse ($J = F \cdot \Delta t$) — are the most direct tools for analyzing impact, collision, and crash events. While energy methods tell you how much energy is involved, momentum methods tell you about the forces during impact and the velocities before and after.

For CAE engineers, momentum thinking is most useful in three contexts: designing energy-absorbing structures (crumple zones, airbags), analyzing impact events in explicit FEM, and interpreting test data from crash labs where force-time histories are measured.

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How does an airbag actually protect you? I mean, the crash still happens — the car still stops. What does the airbag actually change?

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Great question — the crash force and energy don't change, but the airbag changes when they're applied to your body. Your body must go from ~50 km/h to 0 — that's a fixed impulse J = Δp = m × Δv regardless of the airbag. But impulse = F × Δt. The airbag increases the contact time Δt from maybe 2ms (head hits steering wheel) to 20–30ms. That factor of 10–15 in Δt means the peak force on your skull is reduced by the same factor. At 2ms, the force can fracture your skull. At 25ms, it's survivable.

2. Linear Momentum: p = mv

Linear momentum is the product of mass and velocity. It is a vector quantity — direction matters:

$$\mathbf{p} = m\mathbf{v}$$

Newton's Second Law can be written in terms of momentum:

$$\mathbf{F} = \frac{d\mathbf{p}}{dt} = \frac{d(m\mathbf{v})}{dt}$$

For constant mass, this reduces to $\mathbf{F} = m\mathbf{a}$ as expected. But for variable-mass systems — a rocket expelling propellant, a conveyor belt accumulating material — the full form $\mathbf{F} = \frac{d(m\mathbf{v})}{dt}$ must be used.

ObjectMass (kg)Velocity (m/s)Momentum (kg·m/s)
Bullet (9mm)0.0083803.0
Baseball pitch0.145405.8
Car at city speed150014 (50 km/h)21,000
Car at highway speed150033 (120 km/h)49,500
Truck at 80 km/h20,00022440,000

3. Impulse: J = FΔt = Δp

Impulse is the change in momentum produced by a force acting over time:

$$J = \int_{t_1}^{t_2} F(t) \, dt = \Delta p = mv_2 - mv_1$$

For a constant force: $J = F \cdot \Delta t$. The impulse-momentum theorem is just Newton's Second Law integrated over time. Its power lies in relating peak force to contact duration — the same total impulse (momentum change) can be delivered by a small force over a long time, or a large force over a short time.

Force-Time Curves in Crash Testing

In physical crash tests, load cells measure the force-time history at the barrier. The area under the F(t) curve equals the total impulse. Engineers compare FEM-predicted F(t) curves against test data — if the area (impulse) matches but the peak differs, it suggests incorrect crumple zone timing, not wrong total energy absorption.

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In my crash simulation, the peak force is 30% higher than the test but the total deformation looks similar. What could explain that?

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If total impulse (area under F-t curve) is similar but peak is higher, it usually means your simulation crushes the crumple zone too quickly — high initial stiffness followed by a drop. Check the buckling initiation of the front rails: in the real test, slight geometric imperfections trigger buckling earlier and more progressively. In FEM, a perfectly uniform mesh buckles all at once with a higher peak. Try adding slight geometric imperfections to the front rail mesh — a sine-wave offset of 0.1–0.5mm on the rail cross-section triggers more realistic progressive folding.

4. Airbag Design: Impulse in Action

An automotive airbag is an engineering masterpiece of impulse management. The system must:

  1. Detect the crash within ~15ms (accelerometer threshold)
  2. Ignite the inflator propellant
  3. Fully inflate the bag before the occupant reaches it (~25ms after impact)
  4. Begin controlled deflation through vent holes during occupant loading (25–60ms)

Impulse Calculation for a 70 kg Occupant at 50 km/h

$$\Delta p = m\Delta v = 70 \times 13.9 = 973 \text{ N·s}$$

This impulse must be absorbed through the airbag contact. The airbag provides a contact time of about 25ms:

$$F_{\text{avg}} = \frac{\Delta p}{\Delta t} = \frac{973}{0.025} \approx 39 \text{ kN}$$

Compare to a steering wheel impact (Δt ≈ 2ms): $F = 973/0.002 = 487$ kN — over twelve times higher, and certainly fatal. The airbag's vent holes are designed to maintain a constant pressure (and thus constant force) on the occupant throughout the deceleration — this is actually the optimal impulse delivery for minimizing HIC (Head Injury Criterion).

FEM Simulation of Airbag Deployment

Airbag simulation is one of the most complex FEM problems in automotive engineering. It requires:

  • Folded mesh: The bag starts folded; the mesh must unfold realistically (contact self-interaction)
  • Gas dynamics: Ideal gas law $PV = nRT$ governs pressure evolution as gas flows in and out
  • Fabric material: Highly nonlinear, anisotropic, no compression stiffness (wrinkling)
  • Occupant interaction: Contact between inflating bag and moving occupant

LS-DYNA's *AIRBAG_UNIFORM_PRESSURE and Abaqus's fluid-filled cavity approaches both use the impulse framework — the gas pressure force history integrated over the bag surface must equal the impulse required to decelerate the occupant.

5. Conservation of Momentum

When no external forces act on a system, total momentum is conserved:

$$\mathbf{p}_{\text{total}} = \sum_i m_i \mathbf{v}_i = \text{constant}$$

This is Newton's Third Law in integral form — internal forces between bodies in a system always cancel in pairs, leaving total momentum unchanged. Conservation of momentum is the foundation for analyzing multi-body impact events.

Application: Two-Vehicle Collision Analysis

For accident reconstruction (forensic engineering), conservation of momentum allows calculating pre-impact speeds from post-impact skid patterns. For a head-on collision between car A (1500 kg, 50 km/h east) and car B (2000 kg, 30 km/h west):

$$p_A + p_B = (m_A + m_B)v_f \quad \text{(perfectly inelastic, cars lock together)}$$ $$(1500)(+13.9) + (2000)(-8.33) = (3500)v_f$$ $$v_f = \frac{20{,}850 - 16{,}660}{3500} = 1.20 \text{ m/s (east)}$$

The combined wreckage moves east at 1.2 m/s — car A "won" the momentum battle because its momentum slightly exceeded car B's.

6. Elastic and Inelastic Collisions

Collisions are classified by how much kinetic energy is conserved:

Collision TypeMomentum Conserved?KE Conserved?Engineering Example
Perfectly elasticYesYesIdealized billiard balls, atomic collisions
Partially inelasticYesNo (partial loss)Most real structural impacts
Perfectly inelasticYesNo (maximum loss)Cars that lock together, clay hitting a wall

For elastic collisions between two bodies:

$$v_1' = \frac{m_1 - m_2}{m_1 + m_2}v_1, \qquad v_2' = \frac{2m_1}{m_1 + m_2}v_1$$

The coefficient of restitution $e$ quantifies how elastic a collision is: $e = 1$ (perfectly elastic), $e = 0$ (perfectly inelastic).

$$e = \frac{v_2' - v_1'}{v_1 - v_2} = \frac{\text{relative velocity after}}{\text{relative velocity before}}$$

Typical values: hardened steel on steel ≈ 0.6, rubber ball on concrete ≈ 0.8, car crash ≈ 0.1–0.2.

7. Momentum Methods in Explicit FEM

Explicit FEM (LS-DYNA, Abaqus Explicit) is the tool of choice for impact and crash simulation precisely because it naturally handles the momentum dynamics of fast events. The central difference time integration is essentially a direct numerical application of the impulse-momentum theorem:

$$m \cdot \Delta v = F_{\text{net}} \cdot \Delta t \implies v_{n+1} = v_n + \frac{F_n}{m} \Delta t$$

At each time step, the net nodal force $F_n$ is computed from element stresses and contact forces. Dividing by the nodal mass (diagonal mass matrix) gives the acceleration increment, which updates velocity and then position. No matrix inversion — just a scalar division for each node.

Momentum Flux in SPH and Meshfree Methods

For extreme impact problems — hypervelocity impact, explosions, penetration — Smooth Particle Hydrodynamics (SPH) represents the material as particles with mass and velocity. Conservation of momentum is enforced particle-to-particle through kernel-weighted interactions, avoiding mesh distortion that destroys regular FEM elements in these extreme events.

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For a bird strike simulation on a jet engine fan blade, should I model the bird as a solid element mesh or use SPH particles?

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For bird strike, SPH is typically preferred for the bird (or sometimes a "substitute bird" of gelatin/ice composition). The reason is exactly momentum-related: at impact velocities of 200–300 m/s, the bird behaves essentially as a fluid — it flows around the blade and the impulse is delivered as a pressure pulse, not a solid impact. Regular solid elements would undergo extreme distortion and the contact algorithm would fail. SPH naturally handles the large deformation and "splatter" behavior. The blade itself stays as regular FEM elements since it undergoes finite but manageable deformation.

8. Angular Momentum and Rotating Structures

For rotating machinery (turbines, flywheels, motor rotors), angular momentum $\mathbf{L}$ is the rotational analog:

$$\mathbf{L} = I\boldsymbol{\omega}, \qquad \boldsymbol{\tau} = \frac{d\mathbf{L}}{dt} = I\boldsymbol{\alpha}$$

Where $I$ is the moment of inertia tensor and $\boldsymbol{\omega}$ is angular velocity. Conservation of angular momentum explains why a spinning gyroscope resists reorientation and why a suddenly unbalanced turbine rotor creates extreme bearing forces.

In FEM of rotating machinery (cyclic symmetry models, rotating frame analyses), the angular momentum terms appear as Coriolis and centrifugal body forces in the equation of motion:

$$[\mathbf{M}]\ddot{\mathbf{u}} + [\mathbf{C}_{\text{Gyro}}]\dot{\mathbf{u}} + [\mathbf{K}_{\text{Spin}}]\mathbf{u} = \mathbf{F}$$

The gyroscopic matrix $[\mathbf{C}_{\text{Gyro}}]$ (proportional to spin speed $\Omega$) and spin-softening matrix $[\mathbf{K}_{\text{Spin}}]$ are the FEM expressions of angular momentum effects.

9. Cross-Topics

TopicConnectionLink
Newton's LawsF = dp/dt — momentum is the time-integral of Newton's 2nd LawNewton's Laws of Motion
Work & EnergyKinetic energy = ½mv²; momentum and energy together describe collisionsWork and Energy
KinematicsVelocity before/after impact — kinematic result of momentum balanceKinematics
Circular MotionAngular momentum governs gyroscopic and rotating machinery behaviorCircular Motion & Centrifugal Force
Vibration & DynamicsExplicit FEM time integration is momentum-basedVibration & Dynamics