C_h and C_c are heat capacity rates, i.e. mass flow rate times specific heat (m·cp).
Top: counter-flow ε vs NTU curves for C_r = 0, 0.25, 0.5, 0.75, 1.0 with current operating point in red. Bottom: ε of parallel, counter and unmixed cross flow.
The ε-NTU method introduces a dimensionless capacity-rate ratio C_r and a number of transfer units NTU.
$$C_\min = \min(C_h, C_c),\quad C_r = \frac{C_\min}{C_\max},\quad \mathrm{NTU} = \frac{UA}{C_\min}$$Counter-flow effectiveness (with C_r < 1; the limiting case C_r = 1 gives ε = NTU/(1+NTU)):
$$\varepsilon_\text{counter} = \frac{1 - e^{-\mathrm{NTU}(1-C_r)}}{1 - C_r\,e^{-\mathrm{NTU}(1-C_r)}}$$Parallel-flow effectiveness:
$$\varepsilon_\text{parallel} = \frac{1 - e^{-\mathrm{NTU}(1+C_r)}}{1+C_r}$$Cross-flow, both fluids unmixed (approximate):
$$\varepsilon_\text{cross} \approx 1 - \exp\!\left[\tfrac{1}{C_r}\,\mathrm{NTU}^{0.22}\!\left(e^{-C_r\,\mathrm{NTU}^{0.78}} - 1\right)\right]$$Heat duty and outlet temperatures:
$$Q = \varepsilon\,C_\min\,(T_{h,\text{in}}-T_{c,\text{in}}),\quad T_{h,\text{out}} = T_{h,\text{in}} - \frac{Q}{C_h},\quad T_{c,\text{out}} = T_{c,\text{in}} + \frac{Q}{C_c}$$