Outlet relative humidity is fixed at RHout=95% (saturation near the coil surface) and atmospheric pressure at patm=1013 hPa.
X axis = dry-bulb temperature T (°C) / Y axis = humidity ratio w (g/kg DA). Red dot = inlet (In), blue dot = outlet (Out). Horizontal leg = sensible change, vertical leg = latent change, blue curve = saturation line.
From the saturation vapor pressure es(T) and relative humidity RH we obtain the vapor pressure and humidity ratio w, then the specific enthalpy h of moist air per kg of dry air.
Saturation vapor pressure (Magnus formula):
$$e_s(T) = 6.112\,\exp\!\left(\frac{17.62\,T}{243.12+T}\right)\ \text{[hPa]}$$Humidity ratio (per kg of dry air):
$$w = 622\,\frac{e}{p_\text{atm}-e}\ \text{[g/kg DA]}$$Specific enthalpy of moist air:
$$h = 1.006\,T + \frac{w}{1000}\,(2501 + 1.86\,T)\ \text{[kJ/kg DA]}$$Air mass flow rate and heat loads:
$$m_a = V \cdot \rho \approx V \cdot 1.2\ \text{[kg/s]}$$ $$Q_s = m_a\,c_p\,(T_\text{in}-T_\text{out}),\quad Q_L = m_a\,\frac{w_\text{in}-w_\text{out}}{1000}\,L_v$$ $$Q_t = m_a\,(h_\text{in}-h_\text{out}) \approx Q_s + Q_L,\quad \text{SHF} = \frac{Q_s}{Q_t}$$Constants: cp=1.006 kJ/(kg·K), Lv≈2501 kJ/kg, ρ≈1.2 kg/m³. The dehumidification rate is dW = ma(win-wout)/1000 × 3600 [kg/h].