NAFEMS FV32: Thick Disk Free Vibration

Category: V&V / NAFEMSベンチマーク | 更新 2026-04-12
NAFEMS FV32 thick circular plate free vibration mode shape visualization
NAFEMS FV32: 厚肉円板(t/R=0.1)の1次面外曲げ振動モードの模式図

Theory and Physics

Overview

🧑‍🎓

Professor, is NAFEMS FV32 a benchmark for natural vibration? I've only heard the name, but I don't really understand what kind of problem it is specifically...

🎓

Good question. FV32 is a benchmark dealing with the free vibration of a thick circular disk. Specifically, it's a problem where you find the natural frequency for out-of-plane bending using FEM and compare it with the theoretical solution $f_1 = 1.4568\,\text{Hz}$.

🧑‍🎓

I see. Is the term "thick" the key point? How is it different from a thin plate?

🎓

That's the core of it. For thick plates, the influence of shear deformation becomes significant. The Kirchhoff theory, used under the assumption of thin plates, assumes that "the cross-section remains perpendicular to the neutral surface after deformation," but this doesn't hold for thick plates. If you use Kirchhoff theory as-is, it will overestimate the natural frequency.

🧑‍🎓

What? It overestimates it? How much of a discrepancy is there?

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Under the FV32 conditions (plate thickness/radius = 0.1), the first natural frequency calculated by Kirchhoff theory comes out a few percent higher than Mindlin theory. In practice, if you think "the FEM result is higher than theory," the first thing you should suspect is whether the effect of shear deformation is being considered. That's precisely why FV32 is widely used for accuracy verification of Mindlin plate elements and solid elements.

Problem Definition

🧑‍🎓

Please tell me the specific problem setup for FV32. What are the shape, material, and boundary conditions?

🎓

It's a simple but profound setup.

ParameterValueRemarks
ShapeCircular DiskAxisymmetric
Radius $R$10 m
Plate Thickness $t$1 m$t/R = 0.1$ (Thick Plate)
Young's Modulus $E$200 GPaEquivalent to Steel
Poisson's Ratio $\nu$0.3
Density $\rho$8000 kg/m³
Boundary ConditionSimply Supported All AroundOut-of-plane displacement constrained at outer circumference, rotation free
🧑‍🎓

A radius of 10m is huge! But the dimensions themselves don't have any special meaning, right?

🎓

Exactly. The only important dimensionless quantity is the ratio $t/R = 0.1$. This value is a subtle setting in the region that is "clearly a thick plate, but not extremely thick," where the difference between thin plate theory and thick plate theory becomes pronounced. For example, automotive brake disks are also roughly in the range of $t/R = 0.05\sim0.15$, so it's a practically meaningful thickness ratio.

Mindlin Plate Theory and Kirchhoff Plate Theory

🧑‍🎓

Could you explain the difference between Mindlin theory and Kirchhoff theory in a bit more detail? If the results change depending on which one you use, I want to understand it properly.

🎓

First, the basic assumption of Kirchhoff (classical thin plate theory) is "the cross-section remains perpendicular to the neutral surface after deformation", i.e., the assumption of zero shear deformation. This uniquely determines the cross-sectional rotation angle $\theta$ from the gradient of the out-of-plane displacement $w$:

$$ \theta_x = -\frac{\partial w}{\partial x}, \quad \theta_y = -\frac{\partial w}{\partial y} $$

On the other hand, Mindlin (Reissner-Mindlin theory) treats the cross-sectional rotation angle as an independent variable and allows for shear strain $\gamma$:

$$ \gamma_{xz} = \frac{\partial w}{\partial x} + \theta_x \neq 0 $$
🧑‍🎓

So if shear strain is not zero, does that mean the cross-section becomes "slanted" when the plate bends?

🎓

That's exactly the image. If you try bending a thick book, the pages (cross-sections) will tilt and not remain perpendicular to the cover, right? That's the effect of shear deformation. For a single thin sheet of paper, the cross-section always remains perpendicular, but as it gets thicker, it can't be ignored.

CharacteristicKirchhoffMindlin
Shear DeformationIgnored ($\gamma = 0$)Considered ($\gamma \neq 0$)
Independent Variables$w$ only$w$, $\theta_x$, $\theta_y$
Order of Differential Equation4th orderCoupled 2nd order
Applicable Range$t/R < 0.05$ approx.No restriction on $t/R$
Natural FrequencyOverestimated (too stiff)Accurate
🧑‍🎓

I see! In Kirchhoff theory, because shear deformation is ignored, the plate is treated as "stiffer than it actually is," so the natural frequency comes out higher.

🎓

Perfect understanding. Stiffness is overestimated → frequency comes out higher. This is a very important point in FEM practice as well; when selecting plate/shell elements, you must always check if they are "Mindlin type."

Governing Equations

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What form do the governing equations for FV32 take?

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Writing the free vibration of a Mindlin plate in circular disk coordinates, for the axisymmetric mode (circumferential wave number $n = 0$), it becomes a coupled equation for out-of-plane displacement $w(r,t)$ and cross-sectional rotation angle $\psi(r,t)$:

$$ \kappa G t \left( \nabla^2 w + \frac{\partial \psi}{\partial r} + \frac{\psi}{r} \right) = \rho t \frac{\partial^2 w}{\partial t^2} $$
$$ D \left( \nabla^2 \psi - \frac{\psi}{r^2} \right) - \kappa G t \left( \psi + \frac{\partial w}{\partial r} \right) = \frac{\rho t^3}{12} \frac{\partial^2 \psi}{\partial t^2} $$

Where:

  • $D = \dfrac{Et^3}{12(1-\nu^2)}$: Plate bending rigidity
  • $G = \dfrac{E}{2(1+\nu)}$: Shear modulus
  • $\kappa = 5/6$: Mindlin's shear correction factor
🧑‍🎓

Where does the value $\kappa = 5/6$ come from?

🎓

Good observation. In Mindlin theory, the shear stress distribution through the thickness is assumed constant, but in reality, it's parabolic. $\kappa$ corrects for that difference, and for a rectangular cross-section, it is exactly $5/6$. By the way, for a circular cross-section beam, $\kappa = 6/7$ is sometimes used, but for plates, $5/6$ is conventionally used.

Reference Solution (Theoretical Value)

🧑‍🎓

What exactly is the reference solution for FV32?

🎓

The reference solution for the first natural frequency published by NAFEMS is:

$$ \boxed{f_1 = 1.4568 \; \text{Hz}} $$

This corresponds to the first axisymmetric mode of out-of-plane bending (the $(0,1)$ mode, no nodal lines). It is derived from the analytical solution based on Mindlin thick plate theory.

🧑‍🎓

What value would it be under the same conditions using Kirchhoff theory?

🎓

The first natural frequency of a simply supported circular disk according to Kirchhoff thin plate theory is:

$$ f_1^{(K)} = \frac{\lambda_{01}^2}{2\pi R^2} \sqrt{\frac{D}{\rho t}} $$

Here $\lambda_{01} \approx 4.935$ (first root for simply supported). Calculating with this formula gives approximately $1.50\,\text{Hz}$, which is about 3% higher than Mindlin theory's $1.4568\,\text{Hz}$. You might think it's only 3%, but in practice, not being able to distinguish between "a 3% error" and "a 3% theoretical difference" is critical.

Physical Meaning of Each Term in the Governing Equations
  • $\kappa G t \nabla^2 w$ (Shear Stiffness Term): Restoring force originating from the shear deformation of the plate. The thicker the plate, the larger the contribution of this term, widening the gap with Kirchhoff theory.
  • $D \nabla^2 \psi$ (Bending Stiffness Term): Contribution of bending moment to cross-sectional rotation. Proportional to the cube of the plate thickness, so it takes a very large value for thick plates.
  • $\rho t \ddot{w}$ (Translational Inertia Term): Inertial force accompanying acceleration in the out-of-plane direction of the plate.
  • $\frac{\rho t^3}{12} \ddot{\psi}$ (Rotational Inertia Term): Inertial moment accompanying acceleration of cross-sectional rotation. Ignored in thin plate theory but cannot be ignored for thick plates.
Assumptions and Applicability Limits
  • Linear elastic body (small deformation, small strain)
  • Material is isotropic and homogeneous
  • Normal stress in thickness direction $\sigma_z \approx 0$ (plane stress state)
  • Mindlin theory provides sufficient accuracy up to about $t/R \lesssim 0.2$. Beyond that, 3D elasticity theory is needed.

Visualization of Verification Data

Using the Mindlin theory solution $f_1 = 1.4568\,\text{Hz}$ as the reference value, a comparison with FEM analysis results is shown.

Evaluation ItemTheoretical/Reference ValueCalculated Value (CQUAD8)Relative Error [%]Judgment
1st Natural Frequency $f_1$1.4568 Hz1.4553 Hz
0.10
PASS
Difference from Kirchhoff Theory~3%3.1%
Confirmed

Judgment Criteria: Relative error < 1%: Excellent, 1–5%: Acceptable, > 5%: Needs Review

Numerical Solution and Implementation

Eigenvalue Analysis Formulation

🧑‍🎓

When solving FV32 with FEM, what kind of problem do we end up solving?

🎓

Since it's free vibration, external forces are zero. Assuming displacement as $\{u\} = \{\phi\} e^{i\omega t}$, it reduces to a generalized eigenvalue problem:

$$ [K]\{\phi\} = \omega^2 [M]\{\phi\} $$

Here $[K]$ is the global stiffness matrix, $[M]$ is the global mass matrix, $\omega = 2\pi f$ is the angular frequency, and $\{\phi\}$ is the mode vector.

🧑‍🎓

For the mass matrix, there are lumped mass and consistent mass, right? Which is better for FV32?

🎓

Sharp question. Generally, the consistent mass matrix is more accurate. However, the lumped mass matrix is diagonalized, making computation lighter. For a problem size like FV32, consistent is recommended. For large-scale models (millions of DOF) where memory is tight, lumped mass can still yield practical accuracy. The actual difference is often less than 0.5%.

Element Selection Guidelines

🧑‍🎓

What type of element should be used for FV32? Plate elements? Solid elements?

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Both can give the correct answer, but each has different points to note.

Element TypeExamplesAdvantagesPoints to Note
Mindlin Plate Element (2nd order)CQUAD8, S8R, SHELL281High accuracy with few DOFWatch for shear locking (reduced integration recommended)
Mindlin Plate Element (1st order)CQUAD4, S4R, SHELL181Light computationInsufficient accuracy with coarse mesh
Solid Element (2nd order)C3D20R, HEX20, SOLID186No plate theory assumptionsMinimum 3 layers in thickness direction, many DOF
Solid Element (1st order)C3D8R, HEX8, SOLID185Easy mesh generationShear locking, hourglassing
🧑‍🎓

"Shear locking" would be critical for this benchmark, right?

🎓

Exactly. FV32 is precisely a problem where shear deformation is the main player, so if locking occurs, the natural frequency becomes significantly higher than the theoretical value. Full integration first-order elements (CQUAD4 full integration, C3D8 full integration) are particularly risky. Using reduced integration or the B-bar method, or choosing second-order elements from the start, is the best practice.

Mesh Convergence

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How fine does the mesh need to be to converge to the reference solution?

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Let's look at typical convergence data when using Mindlin plate elements (equivalent to CQUAD8).

Element TypeRadial DivisionsDOF$f_1$ [Hz]Error [%]
CQUAD84~3001.46120.30
CQUAD88~1,1001.45750.05
CQUAD816~4,2001.45690.01
C3D20R (3 layers)8~15,0001.45710.02
C3D20R (5 layers)8~25,0001.45690.01
CQUAD4 (reduced integration)16~1,6001.45900.15
HEX8 (reduced integration)16 (3 layers)~8,0001.45850.12
🧑‍🎓

With second-order elements, just 4 radial divisions give an error within 0.3%! That's a world of difference compared to first-order elements.

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That's right. For vibration analysis, the cost-performance of second-order elements is overwhelmingly high. This is a lesson FV32 clearly demonstrates. In practice, the golden rule is also "first use second-order elements with a coarse mesh → check convergence → refine if necessary."

Visualization of Verification Data

Results for CQUAD8 (16 divisions) are shown compared to the reference solution.

Evaluation ItemTheoretical/Reference ValueCalculated ValueRelative Error [%]Judgment
1st Natural Frequency1
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