Natural Convection from a Sphere

Category: Thermal – Natural Convection | Revised 2026-10-01
CAE visualization for sphere natural theory - technical simulation diagram
Natural Convection on Sphere

Theory: buoyant flow around a sphere

Overview

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When a hot sphere cools with no wind, how large is the heat transfer coefficient?

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Air around the sphere warms, becomes lighter and rises — a self-generated flow, natural convection. The flow is weak, so h in air is small, a few to about 20 W/m²K, and radiation of similar size becomes relatively important. Let's compute natural-convection h with Churchill's correlation and, comparing with radiation, calculate the cooling of a hot steel ball and the heat loss from a large spherical hot-water tank.

Churchill's correlation

$$ Nu_D = 2 + \frac{0.589\,Ra_D^{1/4}}{\left[1 + (0.469/Pr)^{9/16}\right]^{4/9}},\qquad Ra_D = \frac{g\beta\,(T_s - T_\infty)\,D^3}{\nu\alpha} $$

Properties are evaluated at the film temperature, with gas expansion coefficient β as its reciprocal.

Radiative heat transfer coefficient

$$ h_r = \frac{\varepsilon\sigma\left(T_s^4 - T_\infty^4\right)}{T_s - T_\infty} $$

With emissivity 0.8, a 300 °C surface in 20 °C surroundings gives about 16 W/m²K — comparable to natural convection.

Coffee Break Trivia

Joining correlations

Stuart Churchill in the US systematised, in the 1970s, a way to join smoothly correlations valid at low and at high values. The '2 + …' and '[1 + (…)^n]^m' forms common in natural-convection correlations come from that idea. For spheres, it joins the Ra → 0 limit Nu = 2 with the large-Ra limit proportional to Ra^(1/4). The approach is still used in many fluid and heat correlations.

Worked examples

Example 1: Rayleigh and Nusselt numbers (Pr 0.71)

Rayleigh numberNusselt number
12.45
10²3.44
10⁴6.54
10⁶16.4
10⁸47.5
10¹⁰146

Example 2: cooling a 10 mm steel ball (300 → 50 °C, 20 °C air)

Cooling modeh at 300 °CTime to 50 °C
Natural convection only20.8 W/m²K818 s
Natural + radiation (ε 0.8)20.8 + 16.3 W/m²K561 s
Fan 5 m/s (no radiation)86.8 W/m²K158 s

The ball's Rayleigh number at 300 °C is about 4,700. As temperature falls so does h, so the cooling was integrated in time.

Example 3: a 1 m spherical tank (60 °C, 20 °C air)

ItemValue
Rayleigh number3.0×10⁹
Natural-convection h2.95 W/m²K
Convective loss371 W
Radiative loss (ε 0.9)791 W
Total (per day)1,161 W (27.9 kWh)
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The tank loses twice as much by radiation as by natural convection.

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As a sphere grows, Nusselt rises but is divided by the diameter, so h actually falls — only about 3 W/m²K at 1 m. Radiative h depends only on temperature: even at 60 °C with emissivity 0.9 it's about 6 W/m²K. So on large vessels and building exteriors radiation often exceeds natural convection, which is why covering insulation with low-emissivity foil like aluminium cuts heat loss so much. For a small steel ball natural convection is larger, yet including radiation still shortens cooling by 30%.

Calculation tips

  1. Evaluate properties at film temperature, updating them in time for cooling problems.
  2. Almost always consider radiation along with natural convection.
  3. Nearby walls or objects obstruct the flow and invalidate the correlation.
  4. With even a slight breeze, compare with forced convection as mixed convection.
  5. In CFD, include buoyancy and make the surrounding domain large enough.
Coffee Break Trivia

“The insulated tank that still cooled”

At one plant, an insulated hot-water tank lost more heat than expected. The calculation had considered only natural convection from the insulation surface. But the surface was painted black with high emissivity, and radiation carried nearly twice the convective loss. Cladding it in aluminium to lower emissivity cut the loss substantially. The smaller the natural-convection coefficient, the more radiation takes the lead.

Common mistakes

Mistakes and fixes

MistakeEffectFix
Ignoring radiationHeat loss halved or worseAdd radiation
Fixed propertiesCooling time wrongUpdate at film temperature
Radius as length scaleRa one-eighthUse diameter
Ignoring nearby obstaclesHeat transfer overestimatedCheck layout
Ignoring slight breezeCooling underestimatedCheck mixed convection
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