Terminal velocity assumes a sphere density of ρ_p = 2700 kg/m³ (aluminum) and gravitational acceleration g = 9.81 m/s².
x = Re (log) / y = C_D (log) / blue line = composite C_D(Re) / red dot = current operating point / dashed lines = regime boundaries
The flow around a sphere changes character with the Reynolds number Re, and the drag coefficient C_D is described by four regime-specific expressions.
Reynolds number, with ρ the fluid density, U the speed, D the diameter and μ the dynamic viscosity:
$$Re = \frac{\rho\,U\,D}{\mu}$$Piecewise drag-coefficient model:
$$C_D = \begin{cases} 24/Re & (Re < 0.1) \\ \dfrac{24}{Re}\bigl(1 + 0.15\,Re^{0.687}\bigr) & (0.1 \le Re < 10^3) \\ 0.44 & (10^3 \le Re < 2\times 10^5) \\ 0.10 & (Re \ge 2\times 10^5) \end{cases}$$Drag force F_D, where A = πD²/4 is the projected area:
$$F_D = \tfrac{1}{2}\,C_D\,\rho\,U^2\,A$$Terminal velocity U_t for a sphere of density ρ_p falling under gravity g:
$$U_t = \sqrt{\tfrac{4}{3}\,\frac{(\rho_p-\rho)\,g\,D}{\rho\,C_D}}$$Since C_D depends on U_t itself, U_t is solved iteratively (five passes here). Near Re ≈ 2*10⁵ the boundary layer trips to turbulence and C_D drops sharply — the drag crisis.