Periodic Heating Problem

Category: Thermal – Transient Conduction | Revised 2026-10-01
CAE visualization for periodic heating theory - technical simulation diagram
Periodic Heating Problem

Theory: a temperature wave that decays and lags

Overview

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Cellars are said to be cool in summer and warm in winter. Can heat conduction explain that?

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Yes. Surface temperature rises and falls daily and yearly, and those changes travel into the ground as temperature waves. The waves shrink with depth and arrive late, so a little deeper the variation is small, and at some depths the seasons are shifted. The same behaviour applies wherever heat enters and leaves periodically: wall insulation and thermal storage, engine-wall temperature swings, ground-source heat. Let's calculate how far and how late the wave reaches in soil.

Periodic solution for a semi-infinite body

$$ T(x,t) = T_m + A\,e^{-x/d}\cos\!\left(\omega t - \frac{x}{d}\right),\qquad d = \sqrt{\frac{2\alpha}{\omega}} = \sqrt{\frac{\alpha P}{\pi}} $$

$A$ is the surface amplitude, $d$ the penetration depth, $P$ the period. Every $d$ the amplitude falls by $1/e$ and the phase lags one radian (about 16% of the period). Longer periods and higher diffusivity reach deeper.

Surface heat flux

$$ q_0(t) = A\sqrt{k\rho c}\,\sqrt{\omega}\,\cos\!\left(\omega t + \frac{\pi}{4}\right) $$

The amplitude of heat entering and leaving the surface is proportional to effusivity $\sqrt{k\rho c}$ and peaks one-eighth of a period (45°) before temperature. High-effusivity materials exchange more heat for the same temperature swing.

Coffee Break Trivia

Fourier and underground temperature

In his 1822 Analytical Theory of Heat, Fourier discussed how surface temperature changes propagate underground, showing the annual wave weakens and lags with depth; he hoped to learn about the Earth's interior heat from underground measurements. Lord Kelvin later estimated the age of the Earth with the same conduction ideas. Today this periodic solution is the basis for estimating ground temperature in designing ground-source heat pumps.

Worked examples

Example 1: daily and annual waves in soil

Diffusivity 5×10⁻⁷ m²/s, conductivity 1.0 W/mK.

ItemDailyAnnual
Penetration depth d0.117 m2.24 m
Depth to 1% amplitude0.54 m10.3 m
Depth of half-period lag0.37 m7.0 m
Amplitude ratio at 10 cm0.430.96
Lag at 10 cm3.3 h62 h

For a 10 K daily surface amplitude, the surface heat-flux amplitude is 121 W/m².

Example 2: comparison with a numerical solution

3 m of soil in 600 cells, driven by a 10 K daily surface cycle for 10 days; the last day was compared with the exact solution.

DepthAmplitude (numerical)Amplitude (exact)Lag (numerical)Lag (exact)
0.1 m4.258 K4.262 K3.25 h3.26 h
0.3 m0.772 K0.774 K9.77 h9.77 h

Example 3: engine combustion-chamber wall

Wall materialPenetration depth (2000 rpm, four-stroke)Depth of 99% decay
Aluminium1.15 mm5.3 mm
Steel0.48 mm2.2 mm
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Combustion swings temperature violently, yet it barely penetrates the wall.

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Combustion cycles run about 17 times a second, so the penetration depth is only about 1 mm in aluminium and 0.5 mm in steel. Only the surface layer swings; inside, the wall sits at a near-constant mean. Overall thermal stress and cooling can therefore be designed on time-averaged heat flux, but the outer few millimetres see repeated thermal strain, a cause of thermal fatigue. With a one-year period in soil, by contrast, the wave penetrates metres and seasons reverse at 7 m. The same formula gives depths differing by orders of magnitude with period and material.

Analysis tips

  1. Compute the penetration depth first and make the domain at least about five times deeper.
  2. Place ten or more grid points within one penetration depth.
  3. Run several periods until periodic steady state and evaluate the last one.
  4. Use a time step of about 1/100 of the period or less.
  5. With several periods (daily and annual), superpose them (for linear problems).
Coffee Break Trivia

“The frost-free depth”

In cold regions, the burial depth of water pipes and foundations depends on how far winter cold reaches underground. Estimating penetration depth from soil properties and the length of winter shows the annual wave falls to about a third of its amplitude at a little over 2 m. Actual frost depth is often shallower still, thanks to latent heat as soil water freezes and insulation by snow. Regional frost depths are set from such conduction reasoning together with observation.

Common mistakes

Mistakes and fixes

MistakeEffectFix
Domain too shallowBottom boundary interferesAt least 5d
Evaluating during start-upWrong amplitude and lagRun several periods
Coarse gridNear-surface gradient wrongTen points per d
Confusing period and angular frequencyWrong dd = √(αP/π)
Ignoring latent heat (freezing)Frost depth wrongInclude phase change
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