Compute speed ratio, torque ratio, and efficiency using the Willis equation. Change tooth counts and watch the animated planetary gear diagram update in real time.
Zs and Zp sliders. You'll see the output speed on the carrier drop dramatically compared to your input speed.The fundamental governing equation for the relative motion in an epicyclic gear train is the Willis Equation. It establishes a fixed kinematic relationship between the rotational speeds of the three main components (Sun, Carrier, Ring), based purely on the gear teeth counts.
$$ \frac{N_{out} - N_c}{N_{in} - N_c}= (-1)^k \frac{Z_s}{Z_r}$$Where:
$N_{out}$ = Rotational speed of the output member (rpm)
$N_{in}$ = Rotational speed of the input member (rpm)
$N_c$ = Rotational speed of the planet carrier (rpm)
$Z_s$ = Number of teeth on the Sun gear
$Z_r$ = Number of teeth on the Ring gear ($Z_r = Z_s + 2 \times Z_p$)
$k$ = Number of meshes between input and output paths. For a simple planetary with an internal ring gear, $k=1$, giving the negative sign that indicates a direction reversal if the carrier is held stationary.
To solve for a specific gear ratio, you must define which member is held stationary (speed = 0). This constraint, combined with the Willis Equation, allows you to calculate the relationship between any input and output. The overall gear ratio is defined as $GR = N_{out}/ N_{in}$.
$$ GR = \frac{N_{out}}{N_{in}}$$For example, with the Ring fixed ($N_r = 0$), the Sun as input ($N_{in}= N_s$), and the Carrier as output ($N_{out}= N_c$), solving the Willis equation yields the speed reduction ratio: $GR = \frac{Z_s}{Z_s + Z_r}= \frac{1}{1 + (Z_r/Z_s)}$. This shows the ratio is always less than 1 (a reduction) and depends solely on the teeth count ratio.
Automatic Transmissions: This is the most common application. Multiple planetary gear sets, combined with clutches and brakes to change which member is fixed, create all the different forward gears and reverse in a car without manually shifting. It allows for smooth, uninterrupted power delivery during gear changes.
Wind Turbine Gearboxes: The low, high-torque rotation of the turbine blades needs to be stepped up to the high speed required by the electrical generator. Planetary stages are used because they are compact and can handle the enormous loads efficiently within the confined nacelle at the top of the tower.
Electric Drill & Power Tool Gearboxes: The high-speed, low-torque output of the universal motor needs to be converted to lower speed and higher torque at the chuck. A compact planetary reduction stage is often used right behind the motor to achieve this in a very space-efficient design.
Aircraft Engine Accessory Drives: In jet engines, a central gearbox (often called the "radial drive" or "transfer gearbox") uses planetary gears to take power off the high-speed engine shaft to drive fuel pumps, hydraulic pumps, and electrical generators at their required, slower speeds.
First, let's clear up the common misconception that "a planetary gear set runs on just one planet gear." In reality, multiple planet gears (typically 3-4) are evenly spaced to share the load, enabling a compact design with high torque. When you change the number of teeth on the planet gear "Z_p" in the simulator, the number of teeth on the ring gear "Z_r" changes automatically, right? This is to satisfy the geometric assembly condition. If this relationship ($Z_r = Z_s + 2 \times Z_p$) is broken, the gears cannot mesh properly. For example, with a sun gear (Z_s=30) and planet gear (Z_p=20), the ring gear must be Z_r=70, or the set cannot be physically assembled.
Next, a frequent mix-up is between speed ratio and torque ratio. Changing the "Input Member" and "Fixed Member" in the tool drastically alters the speed ratio. Pay close attention to the "Output Torque" value here. As the speed ratio (reduction ratio) increases, the torque ratio increases by nearly the same factor (excluding efficiency losses). In other words, if rotation is reduced to 1/10th, torque is amplified by roughly 10 times. Conversely, if the speed ratio is less than 1 (speed increase), torque decreases. If you don't design with this trade-off relationship in mind, you risk failing to achieve your desired output torque.
Finally, a practical pitfall: the calculated efficiency differs from the actual efficiency. The simulator simplifies gear friction and meshing losses with a single efficiency value, but in reality, efficiency varies with rotational speed, load torque, and lubrication conditions. Specifically, the "efficiency" calculated here is a theoretical value assuming tooth surface friction as the primary meshing loss. In an actual mechanism, additional losses like bearing friction and oil churning come into play. The key during initial design before prototyping is to use this calculated value while allowing a margin for motor selection and other decisions.
For an automotive transmission with Zs=30 teeth sun gear, Zp=20 teeth planetary gears, Nin=3000 rpm input, and 3 planetary gears: the speed ratio i calculates to approximately 1.67, producing an output speed of 1798 rpm at 94.2% efficiency accounting for 0.8% mesh losses per gear pair and carrier bearing drag.