Gravity g = 9.81 m/s². Iteration up to 20 steps with convergence |ΔU/U|<1e−4.
Horizontal axis = Reynolds number (log) / Vertical = U_t (log) / Gray dots = D=0.01,0.1,1,10mm theory / Yellow dot = current (Re, U_t) / Dashed lines = regime boundaries Re=0.1, 1000
For a sphere settling under gravity, the terminal velocity is reached when the effective weight is balanced by fluid drag.
General force balance (gravity − buoyancy = drag):
$$U_t = \sqrt{\dfrac{4\,g\,D\,(\rho_p-\rho_f)}{3\,\rho_f\,C_D}}, \qquad Re=\dfrac{\rho_f\,U_t\,D}{\mu}$$Drag coefficient by Reynolds regime:
$$C_D = \begin{cases} 24/Re & (Re<0.1)\\ \dfrac{24}{Re}\,(1+0.15\,Re^{0.687}) & (0.1\le Re<1000)\\ 0.44 & (1000\le Re<2\times10^5) \end{cases}$$In the Stokes regime an explicit solution exists:
$$U_t^{\text{Stokes}} = \dfrac{g\,D^2(\rho_p-\rho_f)}{18\,\mu}$$In the intermediate regime C_D depends on U_t, so we iterate Re→C_D→U_t until convergence.