The BP Reynolds number assumes pipe diameter $D = 10$ mm and mean speed $U = 1$ m/s and uses the plastic viscosity: $Re_{BP} = \rho U D / \mu_p$. Bingham number $Bi = \tau_y / (\mu_p \dot{\gamma})$.
x-axis = shear rate $\dot{\gamma}$ (1/s) / y-axis = shear stress $\tau$ (Pa) / yellow line = Bingham fluid $\tau = \tau_y + \mu_p \dot{\gamma}$ with y-intercept at $\tau_y$ / dashed cyan = Newtonian reference $\tau = \mu_p \dot{\gamma}$ through the origin / yellow dot = current $(\dot{\gamma},\tau)$.
Axisymmetric pipe cross section of radius $R$ / central shaded band = plug flow (rigid core, $r < r_p$) / outer region = viscous shear flow. The plug fraction $r_p / R$ comes from the ratio of yield stress to wall shear stress; a higher Bi makes the plug thicker. Yellow curve = current profile.
Bingham plastic constitutive equation ($\tau_y$ = yield stress in Pa, $\mu_p$ = plastic viscosity in Pa s, $\dot{\gamma}$ = shear rate in 1/s):
$$\tau = \tau_y + \mu_p\,\dot{\gamma}\quad(\tau \ge \tau_y)$$For $\tau < \tau_y$ the material is rigid ($\dot{\gamma} = 0$). The apparent viscosity is $\mu_{\text{app}} = \tau / \dot{\gamma}$:
$$\mu_{\text{app}} = \dfrac{\tau_y}{\dot{\gamma}} + \mu_p$$Bingham number (yield stress vs viscous stress) and BP Reynolds number (defined with $\mu_p$):
$$Bi = \dfrac{\tau_y}{\mu_p\,\dot{\gamma}},\qquad Re_{BP} = \dfrac{\rho\,U\,D}{\mu_p}$$At this tool's defaults ($\tau_y = 20$ Pa, $\mu_p = 0.5$ Pa·s, $\dot{\gamma} = 10$ 1/s, $\rho = 1500$ kg/m³, $D = 10$ mm, $U = 1$ m/s) we get $\tau = 25.0$ Pa, $\mu_{\text{app}} = 2.50$ Pa·s, $Bi = 4.00$ and $Re_{BP} = 30.0$.