The apparent Reynolds number assumes diameter $D = 10$ mm and mean speed $U = 1$ m/s. $\mu_{\text{app}} = K\,\dot{\gamma}^{\,n-1}$, $Re_{\text{app}} = \rho U D / \mu_{\text{app}}$.
x-axis = $\log_{10}\dot{\gamma}$ (1/s) / y-axis = $\log_{10}\tau$ (Pa) / overlay of $\tau(\dot{\gamma})$ for six power-law indices $n$ (0.3, 0.5, 0.7, 1.0, 1.3, 1.7) / yellow dot = current $(\dot{\gamma},\tau)$. The slope is $n$ and the intercept is $\log K$.
Axisymmetric pipe cross section of radius $R$ / x-axis = radial location $r/R$ / y-axis = normalized speed $u/u_{\max}$ / $u(r) = u_{\max}\left[1 - (r/R)^{(n+1)/n}\right]$ / parabolic at n=1, flattened for n < 1, sharpened for n > 1.
Ostwald-de Waele power-law constitutive equation ($K$ = consistency index in Pa s^n, $n$ = power-law index, $\dot{\gamma}$ = shear rate in 1/s):
$$\tau = K\,\dot{\gamma}^{\,n}$$Because the apparent viscosity is $\mu_{\text{app}} = \tau/\dot{\gamma}$, it is constant only for a Newtonian fluid (n=1) and varies with shear rate otherwise:
$$\mu_{\text{app}} = K\,\dot{\gamma}^{\,n-1}$$Laminar pipe-flow velocity profile ($R$ = inner radius, $u_{\max}$ = centerline speed):
$$u(r) = u_{\max}\left[1 - \left(\dfrac{r}{R}\right)^{(n+1)/n}\right]$$Apparent pipe Reynolds number with diameter $D$, mean speed $U$ and density $\rho$:
$$Re_{\text{app}} = \dfrac{\rho\,U\,D}{\mu_{\text{app}}}$$$n < 1$ = shear-thinning (pseudoplastic), $n = 1$ = Newtonian, $n > 1$ = shear-thickening (dilatant). At this tool's defaults ($K = 1$ Pa·sⁿ, $n = 0.5$, $\dot{\gamma} = 10$ 1/s) we get $\tau = \sqrt{10} \approx 3.16$ Pa, $\mu_{\text{app}} = 10^{-0.5} \approx 0.316$ Pa·s and $Re_{\text{app}} \approx 31.6$.