Residence time tau = V/v, Damkohler number Da = k*tau. Both reactors are assumed isothermal, constant-density and first-order in A.
While paused, move the sliders to update the result instantly.
Left = CSTR (perfectly mixed: uniform color = uniform concentration, particles stirred turbulently). Right = PFR (concentration gradient fading from inlet to outlet, particles advancing in plug flow). Bottom = Levenspiel plot 1/(−rA) vs X: the shaded area is proportional to the volume needed for the same conversion (PFR area < CSTR area).
For the first-order reaction A to B (rate $r = k C_A$), the steady-state mass balances of the CSTR and the PFR can be solved as follows. Here tau is the residence time and Da is the dimensionless Damkohler number.
Residence time and Damkohler number:
$$\tau = \frac{V}{v}, \qquad Da = k\,\tau$$CSTR exit concentration (from the steady mass balance $v(C_{A0}-C_A) = k C_A V$):
$$C_{A,\text{CSTR}} = \frac{C_{A0}}{1+Da}$$PFR exit concentration (from integrating $-v\,dC_A/dV = k C_A$ along the tube):
$$C_{A,\text{PFR}} = C_{A0}\,e^{-Da}$$Volume ratio required to reach the same conversion $X$:
$$\frac{V_\text{CSTR}}{V_\text{PFR}} = \frac{-X}{(1-X)\,\ln(1-X)}$$The higher the target conversion, the more rapidly the CSTR volume requirement grows: about 3.9 times at X = 0.9, and 21 times at X = 0.99.