Residence time tau = V/v, Damkohler number Da = k*tau. Both reactors are assumed isothermal, constant-density and first-order in A.
X axis = position inside the reactor z/L (continuous for PFR, single tank for CSTR) / Y axis = [A]/[A]0. Blue solid line = PFR exponential decay, green dashed line = constant CSTR value.
For the first-order reaction A to B (rate $r = k C_A$), the steady-state mass balances of the CSTR and the PFR can be solved as follows. Here tau is the residence time and Da is the dimensionless Damkohler number.
Residence time and Damkohler number:
$$\tau = \frac{V}{v}, \qquad Da = k\,\tau$$CSTR exit concentration (from the steady mass balance $v(C_{A0}-C_A) = k C_A V$):
$$C_{A,\text{CSTR}} = \frac{C_{A0}}{1+Da}$$PFR exit concentration (from integrating $-v\,dC_A/dV = k C_A$ along the tube):
$$C_{A,\text{PFR}} = C_{A0}\,e^{-Da}$$Volume ratio required to reach the same conversion $X$:
$$\frac{V_\text{CSTR}}{V_\text{PFR}} = \frac{-X}{(1-X)\,\ln(1-X)}$$The higher the target conversion, the more rapidly the CSTR volume requirement grows: about 3.9 times at X = 0.9, and 21 times at X = 0.99.