AC Induction Motor Simulator Back
Electric Machinery

AC Induction Motor Simulator

Set the equivalent circuit parameters of a three-phase induction motor and compute the torque-speed (T-N) curve, efficiency, and power factor in real time. Max torque, starting torque, and synchronous speed are calculated automatically.

Motor Parameters
Stator resistance R₁
Ω
Rotor resistance R₂
Ω
Stator reactance X₁
Ω
Rotor reactance X₂
Ω
Magnetizing reactance Xm
Ω
Phase voltage V₁
V
Results
Results
— rpm
Sync. speed ns
— N·m
Max torque
Slip at T_max
— N·m
Starting torque
Torque — Speed Curve (T-N)
Efficiency & Power Factor vs Slip (0 – 0.2)
Theory & Key Formulas
$$T = \frac{3}{\omega_s}\cdot\frac{I_2^2 R_2}{s}$$ $$s_{max}=\frac{R_2}{\sqrt{R_1^2+(X_1+X_2)^2}}$$

$n_s = 120f/p\ [\mathrm{rpm}]$, $\omega_s = 2\pi n_s/60$

What is an AC Induction Motor?

🙋
What exactly is the "slip" in an induction motor? I see it on the simulator's x-axis.
🎓
Basically, slip is how much slower the rotor spins compared to the rotating magnetic field. It's defined as $s = (n_s - n) / n_s$, where $n_s$ is synchronous speed. At standstill (s=1), the motor produces high starting torque. Try moving the "Rotor Resistance" slider above—you'll see how it changes the torque at high slip.
🙋
Wait, really? So if I increase the rotor resistance R₂, the starting torque gets bigger? But then the curve looks... flatter?
🎓
Exactly! You're seeing a key trade-off. More R₂ increases starting torque, but it also moves the point of maximum torque to a higher slip. In practice, this means the motor runs less efficiently at its normal operating speed. A common case is a "deep-bar" rotor design, which effectively has high R₂ at start-up.
🙋
What about those reactance parameters, X₁ and X₂? When I increase them, the whole torque curve seems to drop and the peak shifts left.
🎓
Great observation. Stator and rotor leakage reactance (X₁, X₂) oppose the flow of current. Higher reactance means less current can flow for a given voltage, so torque at any slip is reduced. Crucially, the slip for maximum torque is $s_{max}=R_2 / \sqrt{R_1^2+(X_1+X_2)^2}$. See how (X₁+X₂) is in the denominator? That's why the peak shifts to lower slip (higher speed) when you increase them.

Physical Model & Key Equations

The core performance of an induction motor is described by its torque-speed characteristic. The electromagnetic torque T is proportional to the power dissipated in the rotor resistance, divided by slip.

$$T = \frac{3}{\omega_s}\cdot\frac{I_2^2 R_2}{s}$$

Where $T$ is the developed torque (Nm), $\omega_s$ is the synchronous angular speed (rad/s), $I_2$ is the rotor current referred to the stator (A), $R_2$ is the referred rotor resistance (Ω), and $s$ is the slip.

The motor has a specific slip point where it produces its maximum, or "breakdown," torque. This is a critical design limit.

$$s_{max}=\frac{R_2}{\sqrt{R_1^2+(X_1+X_2)^2}}$$

Here, $R_1$ is the stator resistance, and $X_1$ & $X_2$ are the stator and rotor leakage reactances. This shows that maximum torque occurs at a slip directly proportional to rotor resistance but inversely proportional to the total circuit impedance.

Frequently Asked Questions

The equivalent circuit parameters (especially R2 and the leakage reactance X1+X2') may deviate from the actual motor. Please accurately set the secondary resistance R2 and leakage reactance based on catalog values or measured data.
Increasing the secondary resistance R2 will increase the starting torque (though the maximum torque remains unchanged, shifting to a higher slip side). However, this reduces efficiency, so adjust the balance according to the application.
The current model is fixed at the rated frequency. To change the frequency, manually recalculate the synchronous speed ωs and reactance (proportional to frequency), then modify the parameters accordingly.
At low loads, slip is small and secondary current decreases, while the excitation current (reactive current) becomes dominant, causing the power factor to drop. Additionally, the output ratio relative to fixed losses is small, so efficiency also decreases. This is the same physical phenomenon as in the actual motor.

Real-World Applications

Industrial Pumps and Fans: These are the most common applications. Engineers use simulations like this one to select a motor with a torque curve that ensures smooth acceleration of the fan or pump load to its operating point, which is typically at low slip for high efficiency.

Electric Vehicle Traction Motors: Modern EVs often use induction motors for their robustness and high-speed capability. Designers tweak parameters like rotor resistance to achieve a flat torque curve at low speeds for strong acceleration, while managing reactance to allow high top speeds.

Conveyor Belts and Crushers: These machines require very high starting torque to overcome inertia and load. Motors with higher rotor resistance (like wound-rotor or deep-bar designs) are chosen, a behavior you can directly test in the simulator by cranking up R₂.

Household Appliances (Washers, Compressors): Here, the focus is on reliable, efficient operation at a steady speed. Motors are designed with low leakage reactance to maximize the power factor and efficiency at the normal running slip, reducing electricity costs.

Common Misconceptions and Points to Note

When you start using this simulator, there are a few points that are easy to misunderstand. First and foremost, you might think that "setting the reactance to zero will make performance infinite," but that is incorrect. In reality, coils always generate leakage flux, making it physically impossible to reduce leakage reactance to zero. For example, setting both X₁ and X₂ to 0 will make the maximum torque theoretically infinite, but this is an unrealistic result that ignores magnetic saturation of the iron core and mechanical strength. Secondly, the parameters do not change independently. For instance, if you try to increase the magnetomotive force by adding more winding turns, the coil length inevitably increases, and the resistance R₁ also becomes larger. Understanding this trade-off is key to design. The third pitfall is that the "rated point" is just a single point on the graph. For example, when designing a 1kW output motor, the point with 3% slip and 94% efficiency is the rated point. However, an actual device does not always operate at that exact point; it moves along the curve as the load fluctuates. Therefore, you need to evaluate the characteristics not just at the rated point, but across a wide operating range.

How to Use

  1. Enter stator resistance R1 (ohms) and rotor resistance R2 (ohms) values from motor nameplate or test data.
  2. Input stator reactance X1 and rotor reactance X2 (ohms) based on motor design specifications or measured impedance.
  3. Set supply frequency (typically 50 Hz or 60 Hz) and voltage (230V, 380V, or 460V three-phase).
  4. Specify number of poles to calculate synchronous speed: ns = 120f/P for 60 Hz or 100f/P for 50 Hz.
  5. Click Calculate to generate torque-speed curve, efficiency map, and power factor across slip range 0–100%.

Worked Example

Three-phase 7.5 kW induction motor, 4-pole, 60 Hz supply: R1=1.2Ω, R2=0.8Ω, X1=2.5Ω, X2=2.5Ω, Vs=460V. Synchronous speed ns = (120×60)/4 = 1800 rpm. At slip s=0.04 (rated operation), rotor current develops torque τ ≈ 35 N·m, efficiency η ≈ 92%, power factor ≈ 0.88. Maximum torque occurs near s=0.35, yielding τmax ≈ 65 N·m at approximately 1170 rpm mechanical speed.

Practical Notes

  1. Starting torque at s=1.0 depends critically on rotor resistance; deep-bar or double-cage designs increase τstart by 40–60% versus standard designs.
  2. For energy audits, note that efficiency peaks near rated slip (typically 2–5%); operating significantly below rated load reduces power factor and η noticeably.
  3. Soft-starter or VFD implementation changes effective impedance; account for slip loss conversion to heat when sizing thermal protection.
  4. Verify nameplate R2 against locked-rotor test data; discrepancies indicate winding degradation or manufacturing variation.