$F_b = \rho_f \cdot V \cdot g$
$F_{\text{net}} = F_b - F_g$
Choose fluid type, object shape, and density to compute hydrostatic pressure, buoyancy force, and net force in real time. Watch the object float or sink with an animated pressure gradient visualization.
The hydrostatic pressure at any depth in a fluid at rest increases linearly due to the weight of the fluid above it. The atmospheric pressure at the surface ($P_0$) is added to this.
$$P(h) = P_0 + \rho_f g h$$Where $P(h)$ is the pressure at depth $h$, $\rho_f$ is the fluid density, and $g$ is gravitational acceleration (9.81 m/s²). This means pressure increases by $\rho_f g$ for every meter of depth.
The buoyant force, discovered by Archimedes, is equal to the weight of the fluid displaced by the object. The net vertical force determines if the object floats, sinks, or remains neutrally buoyant.
$$F_b = \rho_f \cdot V_{disp}\cdot g \quad \text{and}\quad F_{\text{net}}= F_b - F_g = (\rho_f - \rho_{obj}) \cdot V \cdot g$$Here, $F_b$ is the buoyant force, $V_{disp}$ is the volume of fluid displaced (equal to the submerged volume $V$), $F_g$ is the object's weight, and $\rho_{obj}$ is the object's density. If $F_{\text{net}}\gt 0$, the object floats; if $F_{\text{net}} \lt 0$, it sinks.
Submarine & Ship Design: Engineers must precisely calculate buoyancy and pressure to ensure submarines can control their depth and surface ships remain stable. The hull must withstand immense hydrostatic pressure at operational depths, which is a direct application of $P(h) = P_0 + \rho g h$.
Dam & Reservoir Engineering: The force on a dam wall is not uniform—it increases linearly with depth. This pressure distribution is critical for designing the dam's thickness and structural reinforcement to hold back millions of tons of water.
Hydrometers & Density Measurement: A hydrometer floats in a liquid, and the depth to which it sinks indicates the fluid's density. This is a direct, practical use of Archimedes' principle, where the buoyant force balances the instrument's weight.
Offshore Oil Platforms: These massive structures rely on buoyancy principles for stability. Their submerged pontoons are designed to displace a specific volume of seawater, providing the precise upward force needed to support the platform's enormous weight above the surface.
Let's go over a few points where people often stumble with these kinds of calculations. First, you might tend to think that "buoyancy is determined by the object's material," but the magnitude of buoyant force is determined solely by the weight of the fluid displaced by the object. The object's own density or material affects the magnitude of gravity (whether it sinks or floats) but does not directly relate to the value of the buoyant force itself. For example, if you submerge a 1m³ block of iron and a 1m³ block of polystyrene foam in water, the buoyant force they experience is exactly the same, approximately 9800N (for water). The difference is that the iron, being heavier than this buoyant force, sinks, while the polystyrene foam floats.
Next, confusing the "center of pressure" with the "center of gravity". This is really important. The center of gravity is the center of the object's mass distribution, determined by its material and shape. On the other hand, the center of pressure is the point where the resultant force from the fluid pressure distribution acts, and it changes with fluid density, object shape, and inclination. For instance, if you submerge a uniform cube vertically in water, its center of gravity is at its geometric center, but the center of pressure is located lower, closer to the bottom face. When these two points are misaligned, the object experiences a rotational moment and tends to tilt. If you select the "flat plate" in the simulator and change the angle of inclination, you should be able to observe the center of pressure moving significantly.
Finally, a pitfall in parameter setting. Be aware that the interpretation of the "characteristic length L" is completely different depending on the shape. For a sphere, it's the diameter; for a cube, it's the side length. When dealing with custom shapes in practical work, if you don't strictly define what this "characteristic length" refers to, your calculation results can become completely meaningless. Also, fluid density changes with temperature (e.g., engine oil density drops significantly when hot). For designs requiring high precision, using the density value at the expected operating temperature is essential.
A steel sphere (ρ = 7850 kg/m³) with diameter 0.5 m submerged to depth h = 3 m in seawater (ρ_fluid = 1025 kg/m³). Volume V = (4/3)π(0.25)³ = 0.0654 m³. Hydrostatic pressure at h = 1.025 × 9.81 × 3 = 30.2 kPa. Buoyancy F_b = 1025 × 9.81 × 0.0654 = 658 N. Object mass m = 7850 × 0.0654 = 514 kg, gravitational force F_g = 514 × 9.81 = 5.04 kN. Net force = 0.658 − 5.04 = −4.38 kN (sinks). Neutral buoyancy density = 1025 kg/m³.