Design Equations
Cylinder:$\sigma_\theta = \dfrac{PD}{2t}$, $\sigma_z = \dfrac{PD}{4t}$
Sphere:
$\sigma = \dfrac{PD}{4t}$
$\sigma_{vm}= \sqrt{\sigma_\theta^2 - \sigma_\theta\sigma_z + \sigma_z^2}$
$t_{min}= \dfrac{PD}{2\sigma_{allow}}$
Instantly compute hoop stress, axial stress, and Von Mises stress for cylindrical or spherical vessels. Evaluate safety factor and minimum wall thickness.
The primary stresses in a thin-wall cylindrical pressure vessel are derived from a simple force balance. The hoop (circumferential) stress resists the bursting force from the internal pressure.
$$\sigma_h = \frac{P D}{2 t}$$Where $\sigma_h$ is the hoop stress, $P$ is the internal pressure, $D$ is the inner diameter, and $t$ is the wall thickness.
The axial (longitudinal) stress resists the force trying to separate the vessel ends. For a cylinder, it is half the hoop stress. To assess failure under this combined stress state, we use the Von Mises equivalent stress.
$$\sigma_{vm}= \sqrt{\sigma_h^2 + \sigma_a^2 - \sigma_h \sigma_a}$$Where $\sigma_{vm}$ is the Von Mises stress and $\sigma_a = \frac{P D}{4 t}$ is the axial stress. The safety factor is then $SF = \frac{\sigma_{yield}}{\sigma_{vm}}$.
Industrial Gas Storage: High-pressure cylinders for oxygen, nitrogen, or acetylene are classic examples. Engineers use these exact calculations to determine the minimum wall thickness needed to safely contain the gas at 200+ bar pressure, selecting materials like high-strength steel or composites.
Boilers and Heat Exchangers: Power plant boilers use banks of pressurized tubes to carry steam. Thin-wall theory is crucial for their initial design, ensuring tubes can withstand operational pressure and temperature cycles without yielding or bursting.
Aerospace Propellant Tanks: Rocket fuel and oxidizer tanks are often thin-wall structures to save weight. The analysis must account for both launch pressures and the fact that hoop stress is the primary design driver, leading to specific welding and inspection protocols for the longitudinal seams.
Food & Beverage Cans: While at lower pressure, the principle is the same. The thin aluminum wall of a soda can is designed to handle the hoop stress from carbonation. The easy-open tab is carefully engineered to not create a stress concentration that would cause a tear.
When starting to use this tool, there are several pitfalls that beginners in CAE often encounter. First and foremost, do not underestimate the definition of "thin-walled." Generally, it refers to cases where the ratio of wall thickness (t) to inner diameter (D) is approximately 1/20 or less (i.e., t/D ≤ 0.05). For example, a vessel with a 1000mm inner diameter and a 60mm wall thickness falls into the "thick-walled" category. Since the tool's fundamental equations consider only membrane stress, the non-negligible radial stress that develops in thick-walled vessels can cause the calculated results to be significantly underestimated compared to reality. In practice, you must always check this ratio.
Next, beware of input errors regarding the "inner diameter." Design drawings often specify the "outer diameter," and if you inadvertently input the outer diameter, the calculated stress will be lower than the actual stress, which is very dangerous. The tool inherently assumes the "inner diameter." Also, pay close attention to the interpretation of the safety factor. The safety factor provided by the tool is a pure margin against yield due to internal pressure. However, in actual design, there are numerous other factors you must consider, such as wall thickness reduction due to corrosion (corrosion allowance), strength reduction at welds (weld joint efficiency), fatigue, and creep. For instance, don't be reassured just because you get a safety factor of 3 for SS400; you need to think, "This value is the basic framework. The actual design safety factor requires further adjustments, like multiplying this by a weld joint efficiency of 0.7..."
Steel cylindrical pressure vessel: diameter D = 500 mm, wall thickness t = 4 mm, internal pressure P = 8 MPa, material yield strength S_y = 280 MPa. Hoop stress σ_h = PD/(2t) = (8 × 500)/(2 × 4) = 500 MPa. Axial stress σ_a = PD/(4t) = 250 MPa. Von Mises stress = √(500² + 250² − 500×250) = 433 MPa. Safety factor = 280/433 = 0.65 (inadequate; increase t to 6 mm for factor ≥ 1.5).