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Transmission Line

Transmission Line · Reflection Coefficient · Impedance Matching

Real-time calculation of reflection coefficient Γ, VSWR, return loss, and input impedance Z_in. Visualize Smith chart, voltage standing wave pattern, and input impedance vs. line length graph.

Parameter Settings
Presets
Characteristic Impedance Z₀
Load Resistance R_L
Load Reactance X_L
Positive: inductive, Negative: capacitive
Line Length d
Fraction of wavelength λ (0 to 2λ)
Attenuation α
Frequency f
Results
|Γ| Reflection Coeff.
∠Γ [°]
VSWR
Return Loss [dB]
Power Delivery [%]
Voltage / Current Standing Wave Pattern
Theory & Key Formulas

Reflection Coefficient:

$$\Gamma = \frac{Z_L - Z_0}{Z_L + Z_0}$$

VSWR: $\mathrm{VSWR}= \dfrac{1+|\Gamma|}{1-|\Gamma|}$

Input Impedance:

$$Z_{in}= Z_0 \frac{Z_L + jZ_0\tan(\beta d)}{Z_0 + jZ_L\tan(\beta d)}$$

$\beta = 2\pi/\lambda$, $d$: line length, Return Loss: $\mathrm{RL}= -20\log_{10}|\Gamma|$ [dB]

What is Impedance Matching?

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What exactly is a "reflection coefficient" in this simulator? I see it's a big number on the chart.
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Basically, it's a measure of how much signal bounces back from a mismatch. The formula is $\Gamma = (Z_L - Z_0)/(Z_L + Z_0)$. If your load impedance $Z_L$ perfectly matches the line's characteristic impedance $Z_0$, $\Gamma$ is zero—no reflection. Try setting the Load Resistance $R_L$ to 50 and Reactance $X_L$ to 0 while keeping $Z_0$ at 50 in the simulator. You'll see the reflection point go to the center of the Smith chart.
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Wait, really? So if it's not zero, what happens? And what's VSWR?
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Good question! A non-zero $\Gamma$ creates standing waves on the line—some points have high voltage, others low. VSWR (Voltage Standing Wave Ratio) quantifies this. It's $\mathrm{VSWR}= (1+|\Gamma|)/(1-|\Gamma|)$. A perfect match gives VSWR=1. A bad mismatch, like setting $R_L$ to 10 ohms with $Z_0=50$, gives a high VSWR. Watch the "Standing Wave Pattern" plot update as you change the sliders—it shows the voltage peaks and nulls.
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Okay, so the "Line Length" slider changes the input impedance? Why does moving the signal down the line change the impedance we see?
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Exactly! That's a key insight. The impedance transforms along the line due to the phase of the reflected wave combining with the forward wave. The simulator uses the formula $Z_{in}= Z_0 \frac{Z_L + jZ_0\tan(\beta d)}{Z_0 + jZ_L\tan(\beta d)}$, where $\beta$ is the phase constant. Slide the "Line Length d" control and watch the blue dot ($Z_{in}$) rotate around the Smith chart. For instance, at $d=\lambda/4$, a short circuit transforms to an open circuit!

Physical Model & Key Equations

The core of transmission line theory is the reflection coefficient, which determines how much of an incident wave is reflected due to an impedance discontinuity.

$$\Gamma = \frac{Z_L - Z_0}{Z_L + Z_0}$$

$\Gamma$ is the complex reflection coefficient. $Z_L = R_L + jX_L$ is the complex load impedance. $Z_0$ is the real characteristic impedance of the transmission line. The magnitude $|\Gamma|$ is between 0 (perfect match) and 1 (total reflection).

The impedance at any point a distance $d$ from the load is not simply the load impedance. It is transformed by the line according to the following equation.

$$Z_{in}(d) = Z_0 \frac{Z_L + jZ_0\tan(\beta d)}{Z_0 + jZ_L\tan(\beta d)}$$

$Z_{in}$ is the input impedance looking into a line of length $d$. $\beta = 2\pi / \lambda$ is the phase constant, where $\lambda$ is the wavelength determined by the frequency $f$. This equation shows how impedance varies periodically with distance, a phenomenon visualized by rotation on the Smith chart.

Real-World Applications

Antenna Feed Design: An antenna might have a feed point impedance of 73 + j42 ohms, but the coaxial cable feeding it has a $Z_0$ of 50 ohms. Engineers use this analysis to design a matching network (like a stub) to minimize reflections, maximizing the power radiated by the antenna instead of being reflected back to the transmitter.

High-Speed PCB Layout: On a computer motherboard, traces carrying multi-gigabit signals must be controlled impedance transmission lines (e.g., 50Ω). If a trace meets a component pin with mismatched impedance, the reflection causes signal integrity issues like ringing. Designers use these calculations to tune trace geometry and add termination resistors.

Quarter-Wave ($\lambda$/4) Transformer: A simple impedance matching device. A section of line with length $\lambda$/4 and a specific $Z_0$ can match two different real impedances. For instance, it can match a 75Ω antenna to a 50Ω cable. The simulator shows this when you set line length to $\lambda$/4 and adjust $Z_0$ to $\sqrt{Z_{in}Z_L}$.

Stub Matching in RF Circuits: A common technique where a short or open-circuited transmission line stub is placed in parallel or series with the main line to cancel out the reactive part of the load impedance. The Smith chart visualization in this tool is essential for designing the correct stub length and position.

Common Misconceptions and Points to Note

There are a few points where many people get tripped up when starting to use this tool. First and foremost, "characteristic impedance $Z_0$ is not just a resistance value." It's completely different from DC resistance; it's determined by the line's structure (conductor thickness, spacing, intervening dielectric) and represents how it 'feels' to a high-frequency signal. Therefore, you can't measure it with a multimeter. For coaxial cable, it's typically 50Ω or 75Ω, and for microstrip lines, you need to calculate or simulate it.

Next, don't judge the "matched" state solely by "reflection coefficient $\Gamma=0$". In practice, $Z_L$ itself usually varies with frequency (e.g., an antenna's resonance characteristics). Even if $\Gamma=0$ at one specific frequency, reflections might be significant across the entire band. If you set $Z_L$ to a complex number (e.g., $50 + j30$) in this tool and vary $l/\lambda$ while considering that the phase constant $\beta l$ changes with frequency (= effective line length changes), you can get a feel for how narrow the matching bandwidth can be.

Finally, interpreting the results. For example, VSWR=2 is often memorized as "acceptable," but this state means approximately 11% of the power is lost to reflection. In high-power applications, this directly leads to heating issues. Also, even if the input impedance $Z_{in}$ becomes purely resistive (imaginary part 0), it doesn't necessarily mean it matches $Z_0$. Be careful, as it might just be the line acting as a transformer, like when $l/\lambda=0.25$.