直角坐标形式与极坐标形式的关系:
$$z = a + jb = r e^{j\theta}= r(\cos\theta + j\sin\theta)$$$r = \sqrt{a^2+b^2}$, $\theta = \arctan(b/a)$, $j^2 = -1$
乘法:$z_1 z_2 = r_1 r_2 \, e^{j(\theta_1+\theta_2)}$, 除法:$\dfrac{z_1}{z_2}= \dfrac{r_1}{r_2}e^{j(\theta_1-\theta_2)}$
阻抗:$Z_R = R$, $Z_L = j\omega L$, $Z_C = \dfrac{1}{j\omega C}$