Plate Buckling

Category: 構造解析 | Integrated 2026-04-06
CAE visualization for plate buckling theory - technical simulation diagram
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Theory and Physics

Differences from Column Buckling

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Euler buckling was for a one-dimensional column. What's different about plate (2D) buckling?


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There are two fundamental differences.


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1. Plates can still carry load after buckling. Columns experience a sudden drop in load capacity after buckling, but plates can redistribute the load and carry additional load after buckling. This is called post-buckling strength.


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2. Plate buckling is a two-dimensional problem. For columns, only deflection in one direction needs to be considered, but plates involve the interaction of in-plane biaxial stress states and out-of-plane deflection.


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Being able to carry load even after buckling is very practical. I've heard aircraft skin panels are like that.


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Exactly. Aircraft wing skin panels undergo local buckling at about 60-70% of the design load, but stiffeners (stringers, ribs) redistribute the load so the overall structure holds. Designs that don't utilize post-buckling strength become excessively heavy, so plate buckling theory is essential in aircraft design.


Governing Equation for Plate Buckling

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What equation governs plate buckling?


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Thin plate buckling is described by the von Kármán equations. For a rectangular plate under uniform compression:


$$ D\nabla^4 w + N_x \frac{\partial^2 w}{\partial x^2} + 2N_{xy} \frac{\partial^2 w}{\partial x \partial y} + N_y \frac{\partial^2 w}{\partial y^2} = 0 $$

Here $D = Et^3 / 12(1-\nu^2)$ is the plate's bending rigidity, $w$ is the out-of-plane deflection, and $N_x, N_y, N_{xy}$ are the in-plane stress resultants.


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$D$ contains the cube of the plate thickness $t$! If the thickness doubles, the bending rigidity becomes 8 times... plate buckling is extremely sensitive to thickness.


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Exactly. Buckling stress is proportional to the square of the plate thickness. Therefore, thickness is the most important parameter in the buckling design of thin plates.


Buckling Coefficient $k$

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I saw the formula $\sigma_{cr} = k \cdot \pi^2 D / (b^2 t)$ in a textbook. What is $k$?


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$k$ is the buckling coefficient, a dimensionless parameter determined by boundary conditions, loading conditions, and the aspect ratio $a/b$. The essence of plate buckling problems boils down to finding this $k$.


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Typical $k$ values:


LoadingBoundary Conditions$k$Remarks
Uniform CompressionFour Edges Simply Supported4.0Base case ($a/b \geq 1$)
Uniform CompressionLoaded Edges Simply Supported + Unloaded Edges Fixed6.97Restraint effect of fixed edges
Uniform CompressionLoaded Edges Simply Supported + One Edge Free0.425Flange outstand plate buckling
Pure ShearFour Edges Simply Supported5.34 + 4.0$(b/a)^2$Shear buckling
Pure BendingFour Edges Simply Supported23.9Bending compression buckling
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There's almost a 10x difference between $k = 4.0$ and $k = 0.425$! Do boundary conditions have that much effect?


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If one edge is free (unrestrained), that edge can deform freely, making buckling easier. The outstand of an H-section steel flange is exactly this case, resulting in a low value of $k = 0.425$. Conversely, the web with both edges fixed has $k = 6.97$ and is more resistant to buckling.


Buckling Mode Shape

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What shape is the buckling mode of a plate?


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The buckling displacement of a simply supported rectangular plate is:


$$ w(x,y) = A \sin\frac{m\pi x}{a} \sin\frac{\pi y}{b} $$

Here $m$ is the number of half-waves in the loading direction. The buckling coefficient $k$ also changes with $m$:


$$ k = \left(\frac{m}{a/b} + \frac{a/b}{m}\right)^2 $$

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The $m$ that minimizes $k$ is the actual buckling mode, right?


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Yes. For a square plate ($a/b = 1$), $m = 1$ gives $k = 4.0$. For $a/b = 2$, $m = 2$ gives $k = 4.0$. Longer plates buckle with more half-waves.


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No matter how long it gets, $k$ converges to $k = 4.0$!


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Exactly. This is an important characteristic of plate buckling: buckling stress is determined solely by the width $b$ (it does not depend on the length $a$). Therefore, in plate buckling design, the "width/thickness ratio" $b/t$ becomes the most important parameter.


Concept of Effective Width

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How does a plate carry load after it buckles?


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When a plate buckles, the central part deflects and its stiffness decreases, but the areas near the supported edges still remain flat and can carry load. This "width of the portion that can still effectively carry load" is the effective width $b_e$.


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von Kármán's effective width formula:


$$ b_e = b \sqrt{\frac{\sigma_{cr}}{\sigma}} = t \sqrt{\frac{k \pi^2 E}{12(1-\nu^2)\sigma}} $$

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The effective width narrows as the applied stress increases... so as the load increases, the effective cross-section of the plate decreases.


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Exactly. Design codes (Eurocode 3, AISI S100, etc.) are based on this effective width concept. Section properties are calculated using the effective width, not the full width, and stress checks are performed on this effective cross-section.


Summary

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Let me organize the theory of plate buckling.


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Key points:


  • Plates can still carry load after buckling — fundamentally different from columns
  • $\sigma_{cr} = k \pi^2 D / (b^2 t)$ — buckling coefficient $k$ is determined by boundary and loading conditions
  • Plate thickness $t$ is dominant — $D \propto t^3$, so sensitivity to thickness is very high
  • For long plates, $k$ is determined solely by width $b$ — $b/t$ is the key to design
  • Effective width — a design concept representing load-carrying capacity after buckling

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So plate buckling is more like "the load path changes" rather than "it breaks."


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Good way to put it. Especially in aerospace and thin-walled steel structures, designs that "allow" buckling are standard, so understanding post-buckling strength and effective width is essential.


Coffee Break Yomoyama Talk

von Kármán and Navier's Analytical Solution for Lattice Buckling

The buckling stress σcr=kπ²E/(12(1-ν²)(b/t)²) for a simply supported rectangular plate (side lengths a×b) under uniformly distributed compression was obtained by Navier (1820s) using the double Fourier series method. The coefficient k varies with the side ratio a/b and boundary conditions; for a square with a/b=1, k=4, and as a/b increases, it fluctuates periodically around a minimum value of k≈4. This formula is the direct basis for the current local buckling checks in thin-walled girder design (AISC, EU codes).

Physical Meaning of Each Term
  • Inertia Term (Mass Term): $\rho \ddot{u}$, i.e., "mass × acceleration". Have you ever experienced being thrown forward when slamming on the brakes? That "feeling of being carried forward" is precisely the inertial force. Heavier objects are harder to set in motion and harder to stop once moving. Buildings shake during earthquakes because the ground moves suddenly while the building's mass "gets left behind". In static analysis, this term is set to zero, which assumes "forces are applied slowly enough that acceleration can be ignored". It absolutely cannot be omitted in impact loading or vibration problems.
  • Stiffness Term (Elastic Restoring Force): $Ku$ or $\nabla \cdot \sigma$. When you stretch a spring, you feel a "force trying to return it", right? That's Hooke's law $F=kx$, and it's the essence of the stiffness term. So, a question—if you pull an iron rod and a rubber band with the same force, which stretches more? Obviously the rubber band. This "resistance to stretching" is the Young's modulus $E$, which determines stiffness. A common misconception: "high stiffness ≠ strong". Stiffness is "resistance to deformation", strength is "resistance to failure"—they are different concepts.
  • External Force Term (Load Term): Body forces $f_b$ (gravity, etc.) and surface forces $f_s$ (pressure, contact forces, etc.). Think of it this way—the weight of a truck on a bridge is a "force acting on the entire volume" (body force), while the force of the tires pushing on the road surface is a "force acting only on the surface" (surface force). Wind pressure, water pressure, bolt tightening force... all are external forces. A common mistake here: getting the load direction wrong. Intending "tension" but it becomes "compression"—sounds like a joke, but it actually happens when coordinate systems are rotated in 3D space.
  • Damping Term: Rayleigh damping $C\dot{u} = (\alpha M + \beta K)\dot{u}$. Try plucking a guitar string. Does the sound keep ringing? No, it gradually fades. That's because vibration energy is converted to heat by air resistance and internal friction in the string. Car shock absorbers work on the same principle—they deliberately absorb vibration energy to improve ride comfort. What if damping were zero? Buildings would keep swaying forever after an earthquake. Since that doesn't actually happen, setting appropriate damping is important.
Assumptions and Applicability Limits
  • Continuum Assumption: Treats material as a continuous medium, ignoring microscopic heterogeneity.
  • Small Deformation Assumption (for linear analysis): Deformation is sufficiently small compared to initial dimensions, and the stress-strain relationship is linear.
  • Isotropic Material (unless otherwise specified): Material properties are independent of direction (anisotropic materials require separate tensor definitions).
  • Quasi-Static Assumption (for static analysis): Ignores inertial and damping forces, considering only the balance between external and internal forces.
  • Non-Applicable Cases: For large deformation/large rotation problems, geometric nonlinearity is required. For nonlinear material behavior like plasticity or creep, constitutive law extensions are needed.
Dimensional Analysis and Unit Systems
VariableSI UnitNotes / Conversion Memo
Displacement $u$m (meter)When inputting in mm, unify loads and elastic modulus to MPa/N system.
Stress $\sigma$Pa (Pascal) = N/m²MPa = 10⁶ Pa. Be careful of unit system inconsistency when comparing with yield stress.
Strain $\varepsilon$Dimensionless (m/m)Note the distinction between engineering strain and logarithmic strain (for large deformations).
Elastic Modulus $E$PaSteel: ~210 GPa, Aluminum: ~70 GPa. Note temperature dependence.
Density $\rho$kg/m³In mm system: tonne/mm³ (= 10⁻⁹ tonne/mm³ for steel).
Force $F$N (Newton)In mm system: N, in m system: N (unified).

Numerical Methods and Implementation

FEM for Plate Buckling Analysis

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When analyzing plate buckling with FEM, are there any specific points to note?


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Plate buckling has more FEM-specific issues compared to column buckling. The biggest challenge is element type selection.


Shell Element vs. Solid Element

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Is it standard to use shell elements for plate buckling?


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Basically, yes. For thin plate buckling analysis, shell elements are standard, and solid elements are used only in special cases.


CharacteristicShell ElementSolid Element
DOF Count (per same area)FewMany (elements needed in thickness direction too)
Bending Deformation AccuracyHigh (faithful to theory)Risk of shear locking
Buckling Waveform RepresentationNaturalDepends on number of elements in thickness direction
Stress Distribution in Thickness DirectionBased on assumptionCan be calculated directly
Applicability to Thick PlatesLimited (approx. $b/t > 10$)No limitation
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