Animation: each gear rotates at its correct angular velocity ratio
Key Formulas
Velocity ratio: $i = N_2/N_1$Pitch circle: $d = m \cdot Z$
Center distance: $a = m(Z_1+Z_2)/2$
Planetary (ring fixed): $n_c = n_s \cdot Z_s/(Z_s+Z_r)$
Calculate reduction ratio, output speed and direction from tooth counts and input rpm. Switch between a spur pair, compound train and planetary gears to compare motion and numerical results.
Animation: each gear rotates at its correct angular velocity ratio
TRY THE SAME CONDITIONS
For a simple pair with N1=20, N2=40, input=1000rpm, module=2mm and no idler, ratio=2.000, output=500rpm and center distance=60.0mm. Ideal torque multiplication is 2.00; the displayed value is 1.96 after the assumed 98% efficiency.
Calculator ↑For a simple pair, i=N2/N1, n2=n1/i, d=mN and a=m(N1+N2)/2. Compound ratios multiply. For a ring-fixed planetary train, Zr=Zs+2Zp and i=1+Zr/Zs. Efficiencies are fixed assumptions: 98%, 98% squared and 97% for the three modes respectively.
In this model it changes output direction, not ratio magnitude. The center-distance card still describes the original gear-pair formula; it is not a complete idler shaft-layout dimension.
Define i as input speed divided by output speed. Without losses, output torque divided by input torque equals i. The displayed torque ratio also includes the assumed efficiency.
Rotation opposite to the input. Ring-fixed and carrier-fixed modes use different output members, so check member roles and direction as well as ratio magnitude.
No. Efficiency is not derived from load, lubrication or materials. Compound and planetary dimensions also use a fixed module of 2mm. Strength and durability require a separate assessment.
Theory reference (not certification of this tool)
KHK: Gear dimensionsExplanation updated: 6 September 2026