Three-Phase Power Calculator Back
Electrical Engineering

Three-Phase Power Calculator

Enter line voltage, line current, and power factor to compute P, Q, S, and PF correction capacitance in real time. Includes phasor diagram and power triangle chart.

Circuit Parameters

VL =
V
IL =
A
PF =
Results
P (kW)
Q (kVAR)
S (kVA)
PF Correction C (μF)
Power components (P / Q / S)
Phasor Diagram
Theory & Key Formulas

$$P = \sqrt{3} V_L I_L \cos\phi$$

三相有効電力 [W]:$V_L$ 線間電圧 [V]、$I_L$ 線電流 [A]、$\cos\phi$ 力率

$$Q = \sqrt{3} V_L I_L \sin\phi, \quad S = \sqrt{P^2+Q^2}$$

無効電力 [VAr] と皮相電力 [VA]:$\sin\phi = \sqrt{1-\cos^2\phi}$

$$V_{phase} = \frac{V_L}{\sqrt{3}}\ \text{(Y接続)},\quad V_{phase}=V_L\ \text{(△接続)}$$

相電圧と線間電圧の関係:Y接続では $V_{phase}\approx0.577V_L$

What is Three-Phase Power?

🙋
What exactly is the difference between "active," "reactive," and "apparent" power in a three-phase system? The simulator shows all three.
🎓
Great question! Basically, think of it like this: Active Power (P) is the "useful" power that does real work, like spinning a motor. Reactive Power (Q) is the power that sloshes back and forth to create magnetic fields in motors and transformers, doing no real work. Apparent Power (S) is the total power the electrical source must supply, combining P and Q. In the simulator, try setting the Power Factor (PF) to 1.0. You'll see Q drop to zero and P equal S—that's the ideal, most efficient case.
🙋
Wait, really? So the "Power Factor" slider controls this relationship? What happens if I set it to a low value, like 0.6?
🎓
Exactly! The Power Factor (PF) is the cosine of the phase angle ($\phi$) between voltage and current. A low PF, like 0.6, means a large phase difference. In practice, for the same voltage and current you entered, the useful power P will be much lower, and the wasteful reactive power Q will be high. The simulator's power triangle will get very tall (showing large Q), and the phasor diagram will show a big angle. This is inefficient—the utility has to deliver more apparent power (S) to get the same useful work done.
🙋
That makes sense. So what's the point of the "Connection Type" selector (Star vs. Delta)? Does it change the power calculation?
🎓
It changes how we relate the line values you measure (VL, IL) to the phase values inside each winding of the motor or generator. In a Star (Y) connection, line voltage is $\sqrt{3}$ times the phase voltage. In a Delta (Δ) connection, line current is $\sqrt{3}$ times the phase current. The total power formulas, which use line values, are the same for both! Try switching the connection type in the simulator while keeping VL and IL constant. You'll see P, Q, and S don't change, proving the formula's consistency.

Physical Model & Key Equations

The fundamental calculation for three-phase power uses the measured line voltage (VL), line current (IL), and the power factor (PF = cos φ). The total apparent power supplied by the source is calculated first.

$$S = \sqrt{3}\times V_L \times I_L$$

Where $S$ is the apparent power in Volt-Amperes (VA), $V_L$ is the line-to-line voltage in Volts (V), and $I_L$ is the line current in Amperes (A). The $\sqrt{3}$ factor arises from the phase relationships in a balanced three-phase system.

The apparent power (S) is then split into its active (real) and reactive components based on the phase angle φ. This forms the "power triangle," which you see visualized in the simulator.

$$P = S \times \cos\phi = \sqrt{3}V_L I_L \cos\phi$$ $$Q = S \times \sin\phi = \sqrt{3} V_L I_L \sin\phi$$

Where $P$ is the active power in Watts (W), $Q$ is the reactive power in Volt-Amperes Reactive (VAR), and $\phi$ is the phase angle. $\cos\phi$ is the Power Factor. $P$ represents useful work, while $Q$ represents energy stored and released by inductive/capacitive elements.

Real-World Applications

Industrial Motor Loads: Large induction motors in factories have a lagging power factor (e.g., 0.8) due to their magnetic coils. Engineers use this exact calculation to size the electrical service for a plant. A low PF results in higher current for the same mechanical output, wasting energy in the wiring.

Power Factor Correction (PFC): This simulator calculates the capacitance needed for PFC. Utilities charge industries extra for low power factor. By adding capacitor banks (which provide leading reactive power), the plant's lagging reactive power is canceled out, bringing the PF closer to 1.0 and reducing penalties.

Data Center & UPS Sizing: The apparent power (S in kVA) is the critical rating for Uninterruptible Power Supplies (UPS) and transformers in data centers. IT equipment draws power at a PF often not equal to 1.0. Engineers must calculate S correctly to avoid overloading the UPS with too much reactive power, even if the active load (servers) seems within limit.

Renewable Energy Inverter Design: Grid-tied solar and wind inverters must control not only the active power (P) they feed into the grid but often also the reactive power (Q) to help stabilize grid voltage. The power triangle model is essential for programming the inverter's control algorithms to meet grid operator requirements.

Common Misunderstandings and Points to Note

When you start using this simulator, there are several points that often trip up beginners, especially those new to CAE. First is the definition of "line-to-line voltage". This literally means "the voltage between lines" and is a measured value. However, it's easy to confuse it with "phase-to-ground voltage" based on single-phase circuit intuition, or to mistake it for "phase voltage (between line and neutral point)" in a wye connection. For example, the 400V displayed by a voltage meter on a distribution panel is the line-to-line voltage. If you set "200V" in the simulator, please input it as the line-to-line voltage from the start.

Next is the sign of the power factor. In this tool, the power factor is a positive value between 0 and 1. However, in some calculation systems, the power factor cosφ is given a sign (positive for lagging, negative for leading) to distinguish between "lagging" and "leading" reactive power Q. Connecting capacitors results in a leading power factor, making the reactive power Q value negative. Changing the power factor in the simulator won't change the sign of Q, but this distinction is crucial in practical engineering calculation sheets.

Finally, the major premise of a "balanced load". The formula used by this tool, $P=\sqrt{3}V_L I_L \cos\phi$, only holds true when the three-phase load is perfectly balanced (each phase impedance is equal). In real-world CAE analysis, such as distribution system fault analysis, unbalanced conditions are the norm. In such cases, different methods like the symmetrical components method are required. It's best to view this simulator as a tool for learning the "basics" of an ideal, balanced state.

How to Use

  1. Enter line voltage (VL) in volts—typical industrial values: 400V, 480V, or 600V three-phase systems
  2. Input line current (IL) in amperes from ammeter readings or motor nameplate data
  3. Enter power factor (PF) between 0.70–1.00; inductive loads like motors typically read 0.80–0.95
  4. Simulator calculates real power (P in kW), reactive power (Q in kVAR), apparent power (S in kVA), and required shunt capacitor value (µF) for unity correction
  5. Review phasor diagram and power triangle to visualize phase displacement and reactive demand

Worked Example

Industrial three-phase motor installation: VL=480V, IL=45A, PF=0.85 (lagging). Real power P = √3 × 480 × 45 × 0.85 = 31.9kW; Apparent power S = √3 × 480 × 45 = 37.5kVA; Reactive power Q = √(37.5² − 31.9²) = 18.6kVAR. To correct to PF=0.95, capacitive reactive power needed = 31.9 × (tan(31.8°) − tan(18.2°)) = 6.8kVAR; equivalent shunt capacitance ≈ 59µF at 480V.

Practical Notes