Quick answer The maximum deflection is δ=PL³/(48EI) for a simply supported beam with a central point load, and δ=PL³/(3EI) for a cantilever with an end point load. The bending stress is σ=M·c/I (with M=PL/4 for a simply supported beam loaded at midspan).
Real-time calculation and visualization of deflection, bending moment, and shear force for simply supported and cantilever beams under concentrated and distributed loads.
Parameters
Beam type
Young's modulus E
GPa
Material stiffness (steel: 200 GPa, Al: 70 GPa)
Second moment of area I
Bending stiffness from the cross-section —
Beam length L
m
Load intensity q
kN
Distributed load (kN/m)
Load position a
m
Load application point on the beam
EI (bending stiffness) —
Results
Max deflection δ_max
—
mm
Max moment M_max
—
kN·m
Max shear force V_max
—
kN
Max deflection angle θ_max
—
°
Bending Stiffness EI
—
N·m²
Beam Model — Click to set load position, drag to adjust magnitude
Click: set load position | Vertical drag: change load magnitude
Beam Bending — the beam visibly deflects under load
—
Load P
—
Max deflection δ [mm]
—
Max moment [kN·m]
—
Max stress σ [MPa]
—
Flexural rigidity EI [N·m²]
—
Position of max δ [m]
Deflection is visually exaggerated. The load rises and falls so the bending is visible—
Deflection curve w(x)
Bending Moment M(x)
Shear force V(x)
Theory & Key Formulas
$$\delta_{\max} = \frac{PL^3}{48EI} \quad (\text{simply supported, central point load})$$
P: load [N], L: span [m], E: Young's modulus [Pa], I: second moment of area [m⁴]
$$\delta_{\max} = \frac{PL^3}{3EI} \quad (\text{cantilever, end point load})$$
A cantilever deflects 16 times more than a simply supported beam (under the same conditions).
Maximum bending stress. c: distance from the neutral axis to the extreme fiber [m]. For a rectangular cross-section, c = h/2.
What is Beam Deflection & Stress Analysis?
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What exactly is "beam deflection," and why is it so important to calculate?
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Basically, it's how much a beam bends under a load. Think of a diving board sagging when someone stands on the end. We need to calculate it to ensure structures like bridges or building floors don't bend too much, which could lead to failure or discomfort. In this simulator, you can see the deflection curve instantly by adjusting the Beam Type and Load Strength q on the left.
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Wait, really? So the bending moment and shear force are different from the deflection? What do those diagrams tell us?
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Exactly! The deflection is the "what you see"—the bent shape. The bending moment and shear force are the internal "stresses" causing that bend. For instance, the bending moment diagram shows where the beam is under maximum tension or compression—a critical spot for cracks to start. Try switching from a cantilever to a simply supported beam above; you'll see the moment diagram flip completely, revealing a different critical point.
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I see the parameter "EI" – Young's modulus E and Second moment of area I. What happens if I make the beam material stiffer or change its cross-section shape?
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Great question! E is the material stiffness (steel vs. rubber), and I depends on the shape's geometry (an I-beam vs. a solid rectangle). Their product EI is the beam's flexural rigidity—its resistance to bending. In practice, to reduce deflection in a floor joist, you'd increase I by making it taller. Slide the E and I sliders down in the simulator and watch the deflection curve shoot up dramatically!
Physical Model & Key Equations
The fundamental governing equation for beam bending, known as the Euler-Bernoulli beam theory, relates the load distribution to the fourth derivative of deflection. This is the equation solved in the background of this simulator.
$$EI\frac{d^4w}{dx^4}= q(x)$$
Where: E = Young's modulus (material stiffness, in Pa) I = Second moment of area (cross-section shape property, in m⁴) w(x) = Deflection at position x (in m) q(x) = Distributed load applied to the beam (in N/m)
For a simply supported beam with a uniform load q, the solution to the above equation gives the deflection curve. This is a classic result you can validate with the simulator.
$$w(x)=\frac{qx(L^3-2Lx^2+x^3)}{24EI}$$
Where: L = Total length of the beam (in m) x = Position along the beam from one support (in m)
The maximum deflection occurs at the center, x = L/2. Notice how deflection scales directly with load q and inversely with EI.
Deflection & Slope Formulas (Maximum Values)
Maximum deflection $\delta_{max}$, slope $\theta$, and maximum bending moment $M_{max}$ for common support and load cases. Here $E$ is Young's modulus, $I$ the second moment of area, $EI$ the flexural rigidity, $L$ the span, $P$ a point load, and $w$ a distributed load.
Support & load
Max deflection $\delta_{max}$
Slope $\theta$
Max moment $M_{max}$
Cantilever, end point load
$PL^3/3EI$
$PL^2/2EI$ (tip)
$PL$ (fixed end)
Cantilever, distributed load
$wL^4/8EI$
$wL^3/6EI$ (tip)
$wL^2/2$ (fixed end)
Simply supported, central point load
$PL^3/48EI$
$PL^2/16EI$ (support)
$PL/4$ (center)
Simply supported, distributed load
$5wL^4/384EI$
$wL^3/24EI$ (support)
$wL^2/8$ (center)
Fixed-fixed, central point load
$PL^3/192EI$
0 at supports (max within span)
$PL/8$ (support & center)
Fixed-fixed, distributed load
$wL^4/384EI$
0 at supports (max within span)
$wL^2/12$ (support), $wL^2/24$ (center)
The stronger the restraint (free < simply supported < fixed-fixed), the smaller the deflection and moment for the same load. For a central point load, the fixed-fixed deflection $PL^3/192EI$ is one quarter of the simply supported value $PL^3/48EI$. Switch the beam type above to verify this numerically.
Allowable Deflection Limits (by application)
Beyond strength, deflection is limited for serviceability (cracking of finishes, door/window fit, vibration, and perceived safety). Typical span-based limits are shown below (always confirm the governing code for your project).
Application
Typical allowable deflection
General floor beams (live load)
$L/250 \sim L/300$
Beams supporting finishes / ceilings
$L/360$
Cantilever (tip)
$L/180 \sim L/250$
Crane girders
$L/500 \sim L/1000$
Precision machinery / machine tool frames
$L/1000$ or stricter
If the limit is exceeded, increase the section ($I$), use a stiffer material, shorten the span, add supports, or reduce the load. Since deflection scales with $L^3$–$L^4$, shortening the span is the most effective.
Section Modulus, Bending Stress, and Choosing the Support
Even when deflection is acceptable, the bending stress must not exceed the allowable value. Bending stress is evaluated with the section modulus $Z$ as $\sigma = M_{max}/Z$, $Z = I/c$ ($c$ = distance from the neutral axis to the extreme fiber), and compared with the allowable stress $\sigma_a$. Deflection checks (rigidity $EI$) and stress checks (section modulus $Z$) are separate — both must be satisfied.
Choosing the support condition: a cantilever has the largest deflection and moment and is used when only one end can be fixed (signs, shelves, machine arms). A simply supported beam is the basic, easy-to-build case. A fixed-fixed beam has small deflection but large negative (hogging) moments at the ends, appearing in rigid frames and continuous structures. Real connections are usually semi-rigid (between pinned and fixed), so a safe-side evaluation brackets the two.
Self-weight: the beam's own weight also acts as a distributed load. For long spans or lightweight designs, self-weight deflection is not negligible, so add it to the live load. In this simulator you can include an equivalent self-weight term in the load input.
Frequently Asked Questions
The unit for deflection is mm, for bending moment is N·mm, for shear force is N, and for stress is MPa. These depend on the units of the input values (length in mm, load in N, Young's modulus in MPa), so please ensure a consistent unit system when entering data.
Yes, they can be set simultaneously. You can add a concentrated load at any position on the beam and also superimpose a distributed load for calculation. The results are displayed as the linear superposition of the effects of each load.
For a rectangular cross-section, enter the width b and height h in mm, and the second moment of area I will be automatically calculated. For a circular cross-section, enter the diameter d. For an arbitrary cross-section, you can directly input the value of I.
Consider increasing the cross-sectional dimensions, changing to a material with a higher Young's modulus, adding support points to shorten the span length, or reducing the load. You can modify each parameter in the simulator and check the effects in real time.
Real-World Applications
Bridge Design: Engineers use this exact analysis to determine the required depth and material for bridge girders. They must limit deflection under the weight of traffic (a distributed load) and heavy trucks (point loads) to prevent excessive sway and ensure long-term fatigue life.
Building Floor Systems: The floor you're standing on is analyzed as a beam. Calculating deflection ensures it doesn't feel "bouncy" under furniture and people (uniform load) and can support heavy items like a water tank (a point load). The bending moment diagram identifies where to place reinforcing steel.
Automotive Chassis: The vehicle's frame is a complex beam system. Simulating deflection and stress from engine weight and road forces helps optimize the design for safety and handling, ensuring the chassis is stiff enough to protect the passenger cabin.
Industrial Machine Frames: Precision machines like CNC mills or printing presses require extremely rigid frames. Even tiny deflections under the motor's forces (modeled as point loads) can cause misalignment and ruin product quality, making this analysis critical.
Common Misconceptions and Points to Note
Let's go over a few points where people often stumble when starting to use this type of tool. First, you might tend to think "Young's modulus E and the second moment of area I are independent parameters", but in reality, changing the material can affect not only E but also I. For example, when switching from a steel (E=210GPa) square pipe to an aluminum (E=70GPa) one, to maintain strength you'd likely increase the wall thickness or the cross-sectional size, right? This also increases I, so the deflection won't simply triple just because E becomes one-third. Using this tool to try things out—like reducing E to 1/3 and then perhaps doubling I—gets you closer to reality.
Next, understand the limits of the "point load" model where the entire force acts at a single point. In the real world, force is almost never applied at a true "point". For instance, when a machine part is bolted down, the load is distributed around the bolt hole. The result you get from setting a concentrated load P=1000N in this simulator implicitly indicates that high stress concentrations will occur in its vicinity in reality. When considering a safety factor, you need to keep this "idealization" in mind.
Finally, remember that small deflection does not automatically mean "OK". Stiffness is certainly important, but in some cases, like with an automobile suspension arm, a certain degree of flexibility is necessary for shock absorption. Also, for the fixed end of a cantilever beam, the bending stress $\sigma = \frac{My}{I}$ (where M is the bending moment and y is the distance to the edge of the cross-section) that occurs there is a more direct criterion for failure than the deflection itself—it must not exceed the material's yield strength. Get into the habit of reviewing results from both the deflection and stress perspectives.
Select beam type (simply supported or cantilever) from the configuration menu.
Enter Young's modulus (eVal, GPa) using the slider or text field—typical values: steel 200 GPa, aluminum 69 GPa, concrete 30 GPa.
Define second moment of inertia (iSliderNum, mm⁴) based on cross-section geometry or select a standard profile.
Set beam length (lVal, mm) using lSlider; range 500–5000 mm typical for structural applications.
Apply loads (pVal, kN) as point loads or distributed loads via pSlider; simulator calculates deflection, bending moment, and shear force in real time.
Worked Example
Steel I-beam (W200x21.5): E=200 GPa, I=21,400 mm⁴, length=3000 mm, simply supported with 15 kN central point load. Calculated maximum deflection: δ=8.2 mm at midspan. Maximum bending moment: M=22.5 kN·m at center. Maximum shear force: V=7.5 kN at supports. Stress: σ=210 MPa (below 250 MPa yield for mild steel).
Practical Notes
Cantilever beams under uniform 5 kN/m load over 2 m produce 2.7× higher deflection than simply supported equivalents; verify support fixity in field.
Always check deflection limits: L/250 for floor beams, L/180 for roof members per building codes.
Temperature effects: aluminum deflection increases 1.5% per 10°C rise due to thermal expansion and reduced E; steel negligible.
Standards & Assumptions
Standard / formula: Euler–Bernoulli beam theory. Simply supported, central point: \( \delta_{\max}=PL^3/(48EI) \); simply supported, UDL: \( \delta_{\max}=5qL^4/(384EI) \); cantilever, end point: \( \delta_{\max}=PL^3/(3EI) \); cantilever, UDL: \( \delta_{\max}=qL^4/(8EI) \). Shear and moment satisfy \( dM/dx=V \). Sources: Gere & Goodno, Mechanics of Materials; Roark's Formulas for Stress and Strain.
Assumptions: Linear-elastic, isotropic, homogeneous material; small deflection; slender beam with plane sections remaining plane (shear deformation neglected, Bernoulli hypothesis); idealized point / uniformly distributed loads. With defaults E=200 GPa, I=1×10⁻⁶ m⁴, L=2 m, P/q=10, the deflection, moment and shear match the formulas above exactly.
Scope & limits: Valid for slender beams (large span/depth). For short, deep beams shear deflection is not negligible and this tool under-predicts (use Timoshenko beam theory). Buckling, large deflection, plasticity and dynamic response are out of scope — an educational static linear model.
Example
Example: I-beam (simply supported, central point load)
SS400 I-beam H-200×100(I = 1.84×10⁻⁵ m⁴), with a 50 kN concentrated load at midspan of 5m:
E = 206 GPa
Maximum deflection: δ = PL³/(48EI) = 50000×5³/(48×206×10⁹×1.84×10⁻⁵) ≈ 34.35 mm
Allowable deflection (L/300): 5000/300 ≈ 16.7 mm → 34.35 mm exceeds the limit → NG (increase section or reduce span)
Use sliders to vary load, span, and second moment of area to check sensitivity.