薛定谔方程的解:
$$E_n = \frac{n^2\pi^2\hbar^2}{2mL^2}, \quad \psi_n(x) = \sqrt{\frac{2}{L}}\sin\!\left(\frac{n\pi x}{L}\right)$$能级间能量差:$\Delta E_{n\to n+1}= E_1(2n+1)$
叠加态的时间演化:$\Psi(x,t)=\dfrac{1}{\sqrt{2}}\!\left[\psi_{n_1}e^{-iE_{n_1}t/\hbar}+\psi_{n_2}e^{-iE_{n_2}t/\hbar}\right]$
振动周期:$T = \dfrac{2\pi\hbar}{|E_{n_2}-E_{n_1}|}$